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Question

Why a fielder in the ground gradually pulls his hands backward while catching a fast moving cricket ball?

This question was previously asked in
NDA 2 2025 GAT Question Paper (14-Sep-2025)
The correct answer is
To reduce the acceleration of the ball

Fielder's Action Explained: Reducing Ball's Acceleration

When a fielder catches a fast-moving cricket ball, they gradually pull their hands backward. This action might seem counterintuitive, but it's based on fundamental principles of physics, specifically related to impulse and momentum.

Understanding Momentum and Impulse

Momentum is a measure of an object's motion and is calculated as the product of its mass (\(m\)) and velocity (\(v\)). The formula is:

\( p = m \times v \)

A fast-moving cricket ball has a significant amount of momentum.

Impulse is the change in momentum of an object. It is also equal to the average force (\(F_{avg}\)) applied multiplied by the time interval (\(\Delta t\)) over which the force is applied. The impulse-momentum theorem states:

\( J = \Delta p = F_{avg} \times \Delta t \)

Where \(\Delta p\) is the change in momentum.

The Fielder's Technique

To catch the ball, the fielder needs to bring its momentum from its initial value (\(p_{initial}\)) to zero (\(p_{final} = 0\)). This means the change in momentum (\(\Delta p\)) is fixed:

\( \Delta p = p_{final} - p_{initial} = 0 - p_{initial} = -p_{initial} \)

The negative sign indicates the change is in the opposite direction of the initial motion.

According to the impulse-momentum theorem (\(F_{avg} \times \Delta t = \Delta p\)), the fielder must apply an impulse to change the ball's momentum. They can do this in two ways:

  • By applying a large force over a short time.
  • By applying a smaller force over a longer time.

A fielder pulls their hands backward to increase the time interval (\(\Delta t\)) during which they are in contact with the ball. By increasing \(\Delta t\), they decrease the average force (\(F_{avg}\)) required to bring the ball to rest, since \(\Delta p\) is constant.

\( F_{avg} = \frac{\Delta p}{\Delta t} \)

This reduced average force also means a reduced average acceleration (\(a\)) of the ball, as described by Newton's second law (F = ma):

\( a_{avg} = \frac{F_{avg}}{m} \)

Reducing the acceleration minimizes the impact force on the fielder's hands, preventing injury and allowing for a secure catch.

Analysis of Options

  • 1. To reduce the acceleration of the ball: This is correct. By increasing the time of contact (\(\Delta t\)), the fielder reduces the average force and consequently the acceleration acting on the ball (and their hands).
  • 2. To increase the acceleration of the ball: This is incorrect. The goal is to stop the ball, which requires decreasing its acceleration (deceleration), not increasing it.
  • 3. To increase the velocity of the ball: This is incorrect. Catching a ball involves reducing its velocity to zero, not increasing it.
  • 4. None of above: This is incorrect because option 1 accurately explains the physics involved.

Therefore, the primary reason a fielder pulls their hands backward is to reduce the acceleration (and the associated force) acting on them by increasing the time over which the ball's momentum is changed.

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