A ball is thrown up with a certain velocity, it attains 50 m and come back to the thrower then the
Total displacement is zero
The question describes a scenario where a ball is thrown vertically upwards with a certain velocity, reaches a maximum height, and then returns to the thrower. We need to determine the total distance covered and the total displacement.
Let's first clarify the key terms:
The ball is thrown upwards and reaches a maximum height of 50 meters from the thrower. It then falls back down to the thrower. The path taken is:
The total distance covered is the sum of the distance traveled upwards and the distance traveled downwards.
Total Distance = Distance (up) + Distance (down)
Total Distance = 50 m + 50 m = 100 m
So, the total distance covered by the ball is 100 meters.
Displacement is the change in position. We need to compare the initial position with the final position.
Since the ball starts and ends at the same location, its initial position is the same as its final position.
Displacement is calculated as:
Displacement = Final Position - Initial Position
In this case, since the initial and final positions are identical, the change in position is zero.
Total Displacement = 0 meters
Therefore, the total displacement of the ball is zero.
For the described motion where the ball goes up 50 m and comes back to the thrower, the total distance is 100 m, and the total displacement is 0 m.
Reviewing the options:
Based on our calculations, the correct statement is that the total displacement is zero.

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