The force-time (\(F-t\)) graph of a 10 kg object initially at rest is shown below. What is the final speed of the object?
The impulse is the area under the force–time graph: \(J=\tfrac12(5)(20)+(15)(20)+\tfrac12(5)(20)=400\) N·s. Since the object starts from rest, \(v=J/m=400/10=40\) m/s.
Important Questions from Newton's Laws of Motion
Weight and mass of an object are defined with Newton’s laws of motion. Which among the following is true ?
Which one of the following is not a contact force?
If an object moves at a non-zero constant acceleration for a certain interval of time, then the distance it covers in that time
A rigid body of mass 2 kg is dropped from a stationary balloon kept at a height of 50 m from the ground. The speed of the body when it just touches the ground and the total energy
when it is dropped from the balloon are respectively
(acceleration due to gravity = 9·8 m/s -2 )A body has a free fall from a height of 20 m. After falling through a distance of 5 m, the body would
