What is the number of diagonals of an octagon?
20
A polygon is a closed shape made up of straight line segments. A diagonal is a line segment that connects two non-adjacent vertices of a polygon. The question asks for the number of diagonals in an octagon.
An octagon is a polygon with 8 sides. It also has 8 vertices. Examples of octagons include a stop sign.
To find the number of diagonals in any polygon, we can use a specific formula. For a polygon with 'n' sides (and hence 'n' vertices), the number of diagonals is given by:
Number of diagonals \(= \frac{n(n-3)}{2}\)
Let's break down this formula:
For an octagon, the number of sides, 'n', is 8.
Using the formula for the number of diagonals:
Number of diagonals of an octagon \(= \frac{n(n-3)}{2}\)
Substitute \(n=8\) into the formula:
Number of diagonals \(= \frac{8(8-3)}{2}\)
Calculate the value inside the parenthesis:
Number of diagonals \(= \frac{8(5)}{2}\)
Multiply the numbers in the numerator:
Number of diagonals \(= \frac{40}{2}\)
Divide to find the final number:
Number of diagonals = 20
So, an octagon has 20 diagonals.
The calculation shows that for a polygon with 8 vertices, there are 20 unique line segments connecting non-adjacent vertices. This is significantly more than the number of sides (8).
| Polygon Name | Number of Sides (n) | Formula: \(\frac{n(n-3)}{2}\) | Number of Diagonals |
|---|---|---|---|
| Triangle | 3 | \(\frac{3(3-3)}{2} = \frac{3(0)}{2}\) | 0 |
| Quadrilateral | 4 | \(\frac{4(4-3)}{2} = \frac{4(1)}{2}\) | 2 |
| Pentagon | 5 | \(\frac{5(5-3)}{2} = \frac{5(2)}{2}\) | 5 |
| Hexagon | 6 | \(\frac{6(6-3)}{2} = \frac{6(3)}{2}\) | 9 |
| Heptagon | 7 | \(\frac{7(7-3)}{2} = \frac{7(4)}{2}\) | 14 |
| Octagon | 8 | \(\frac{8(8-3)}{2} = \frac{8(5)}{2}\) | 20 |
| Nonagon | 9 | \(\frac{9(9-3)}{2} = \frac{9(6)}{2}\) | 27 |
| Decagon | 10 | \(\frac{10(10-3)}{2} = \frac{10(7)}{2}\) | 35 |
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