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Question

Which of the following statements are true regarding the operation of JK flip-flop ?

1. When K input is low and J input is high, the Q output of the flip flop is reset.
2. When K input is high and J input is low, the output Q of the flip flop is set.
3. When both the inputs K and J are low, the output Q does not change.
4. When both the inputs K and J are high it is possible to set or reset the flip-flop (ie) the output toggle on next positive clock edge.

Which one of the following is true ?

This question was previously asked in
UGC NET 2014 Paper 2 History Question Paper (28-Dec-2014)
The correct answer is

3 and 4

 Check each statement against the characteristic table — the first two have set and reset the wrong way round.

JKQn+1Action
00QnNo change
010Reset
101Set
11\(\overline{Q_{n}}\)Toggle

Statement 1 says J high, K low gives a reset — false. J is the set input, so J = 1, K = 0 sets Q to 1.

Statement 2 says K high, J low gives a set — false for the same reason reversed: K is the reset input, so this combination clears Q to 0.

Statement 3 is true. With both inputs low the flip-flop holds its state, which is what makes it a one-bit memory.

Statement 4 is true and describes the toggle mode, the feature the J-K possesses and the S-R does not.

So 3 and 4 — option 2.

The mnemonic that prevents the mix-up : J is for "jump up" (set) and K is for "kill" (clear). Alphabetically, J comes first and corresponds to the higher output.

The characteristic equation encodes all four rows at once:

\(Q_{n+1}=J\overline{Q_{n}}+\overline{K}Q_{n}\)

Substituting J = 1, K = 0 gives \(Q_{n+1}=\overline{Q_{n}}+Q_{n}=1\) — set, confirming statement 1 false. Substituting J = 0, K = 1 gives \(Q_{n+1}=0\) — reset, confirming statement 2 false.

Statement 4's mention of the positive clock edge is important. The toggle mode is exactly where a level-triggered J-K would fail: if the clock stayed high longer than the propagation delay, the output would toggle repeatedly within one pulse — the race-around problem. Edge triggering, or the master-slave arrangement, guarantees precisely one toggle per clock, which is why every practical J-K is edge-triggered.

Hence, the true statements are 3 and 4.

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Important Questions from Sequential Circuits

  1. A basic memory storage element in a digital system is:

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