All Exams Test series for 1 year @ ₹349 only
Question

Two planets $P_1$ and $P_2$ with equal mass have radii $R_1$ and $R_2$, respectively, where $R_2 = \frac{R_1}{2}$. The escape speeds of $P_1$ and $P_2$ are $v_1$ and $v_2$, respectively. Then $\frac{v_2}{v_1}$ is :

This question was previously asked in
NEET UG Re-Exam 2026 Question Paper (21-Jun-2026)
The correct answer is
$\sqrt{2}$

Escape Speed Calculation for Planets

The escape speed ($v_e$) from the surface of a planet is given by the formula:

$ v_e = \sqrt{\frac{2GM}{R}} $

where $G$ is the universal gravitational constant, $M$ is the mass of the planet, and $R$ is its radius.

Step-by-Step Derivation

  1. Identify Given Information:

    • Masses are equal: $M_1 = M_2 = M$.
    • Radii are $R_1$ and $R_2$.
    • Relationship: $R_2 = \frac{R_1}{2}$.
    • Escape speeds are $v_1$ and $v_2$.
  2. Write Escape Speed Formulas:

    • For Planet $P_1$: $v_1 = \sqrt{\frac{2GM_1}{R_1}} = \sqrt{\frac{2GM}{R_1}}$.
    • For Planet $P_2$: $v_2 = \sqrt{\frac{2GM_2}{R_2}} = \sqrt{\frac{2GM}{R_2}}$.
  3. Calculate the Ratio $\frac{v_2}{v_1}$:

    Divide the expression for $v_2$ by the expression for $v_1$:

    $ \frac{v_2}{v_1} = \frac{\sqrt{\frac{2GM}{R_2}}}{\sqrt{\frac{2GM}{R_1}}} $

    Simplify the ratio:

    $ \frac{v_2}{v_1} = \sqrt{\frac{\frac{2GM}{R_2}}{\frac{2GM}{R_1}}} = \sqrt{\frac{R_1}{R_2}} $

  4. Substitute the Radius Relationship:

    Substitute $R_2 = \frac{R_1}{2}$ into the ratio:

    $ \frac{v_2}{v_1} = \sqrt{\frac{R_1}{\frac{R_1}{2}}} = \sqrt{\frac{2 R_1}{R_1}} = \sqrt{2} $

The ratio $\frac{v_2}{v_1}$ is $\sqrt{2}$.

Was this answer helpful?

Similar Questions

  1. The power of a crane, which lifts a mass of $1000 \text{ kg}$ to a height of $20 \text{ m}$ in $10 \text{ s}$ is : 
    ($g = 9.8 \text{ m/s}^2$)

  2. The magnitude and direction of the acceleration produced in a body of mass $5 \text{ kg}$ when two mutually perpendicular forces $8 \text{ N}$ and $6 \text{ N}$ act on it, are respectively :
  3. A box of mass $15 \text{ kg}$ is kept on the floor of a stationary trolley. The coefficient of static friction between the box and the trolley is $0.12$. Keeping the box in stationary state over the trolley, the maximum acceleration with which the trolley can be moved horizontally is : ($g = 10 \text{ m/s}^2$)
  4. The amount of work done to raise a mass 'm' from the surface of the Earth to a height equal to the radius of the Earth 'R', will be :
  5. A thin wire of length 'L' and linear mass density 'm' is bent into a circular ring (in x-y plane) with centre 'C' as shown in figure. The moment of inertia of the ring about an axis yy' (tangent in the plane) will be :

  6. When a ruler falls vertically, 5 different persons catch it with different reaction times. ($g = 9.8 \text{ m s}^{-2}$)
    A. Person A has reaction time of $0.20 \text{ s}$.
    B. Person B has reaction time of $0.22 \text{ s}$.
    C. Person C has reaction time of $0.18 \text{ s}$.
    D. Person D has reaction time of $0.19 \text{ s}$.
    E. Person E has reaction time of $0.21 \text{ s}$.
    What is the correct order of the distance travelled by the ruler for each person ?
  7. The angular speed of a flywheel is increased from $600 \text{ rpm}$ to $1200 \text{ rpm}$ in $10 \text{ s}$. The number of revolutions completed by the flywheel during this time is :
  8. A frictionless circular wire of unit radius is fixed on the horizontal plane. Two point particles of unit mass start moving simultaneously from point $A \left( \theta = \frac{\pi}{2} \right)$ with identical uniform angular speeds in opposite directions, and meet again at point $B \left( \theta = -\frac{\pi}{2} \right)$. During this time, which of the following figures schematically represent the magnitude of the total linear momentum $\vec{P}$ of the system, as a function of $\theta$?

     

  9. A car travels on a circular racetrack of radius $50\text{ m}$, which is banked at an angle $\theta$. If the car travels at a speed $10\text{ ms}^{-1}$, then the wear and tear on its tyres is minimum. Taking the acceleration due to gravity to be $10\text{ ms}^{-2}$, the value of $\theta$ is :
  10. Consider a particle moving along a straight line, whose position as a function of time is given by $s(t) = \alpha t^2 - \beta t + \gamma$, where $\alpha = 1\text{ ms}^{-2}$, $\beta = 6\text{ ms}^{-1}$ and $\gamma = 5\text{ m}$. The average speed of the particle, in $\text{ms}^{-1}$, from $t = 0$ to $t = 6\text{ s}$ is :

Important Questions from Mechanics

  1. A soap bubble of surface tension $0.04 \text{ N/m}$ is blown to a diameter of $7 \text{ cm}$. If $(15000 - x) \text{ }\mu\text{J}$ of work is done in blowing it further to make its diameter $14 \text{ cm}$, then the value of $x$ is _______.
    ($\pi = 22/7$)
  2. A uniform solid cylinder of length $L$ and radius $R$ has moment of inertia about its axis equal to $I_1$. A small co-centric cylinder of length $L/2$ and radius $R/3$ carved from this cylinder has moment of inertia about its axis equals to $I_2$. The ratio $I_1/I_2$ is _______.
  3. A fly wheel having mass $3\text{ kg}$ and radius $5\text{ m}$ is free to rotate about a horizontal axis. A string having negligible mass is wound around the wheel and the loose end of the string is connected to $3\text{ kg}$ mass. The mass is kept at rest initially and released. Kinetic energy of the wheel when the mass descends by $3\text{ m}$ is _________ $\text{J}$. ($g = 10\text{ m/s}^{2}$)
  4. Suppose there is a uniform circular disc of mass $M \text{ kg}$ and radius $r \text{ m}$ shown in figure. The shaded regions are cut out from the disc. The moment of inertia of the remainder about the axis $A$ of the disc is given by $\frac{x}{256} M r^2$. The value of $x$ is ________.

  5. A ball of radius $r$ and density $\rho$ dropped through a viscous liquid of density $\sigma$ and viscosity $\eta$ attains its terminal velocity at time $t$, given by $t = A \rho^a r^b \eta^c \sigma^d$, where $A$ is a constant and $a$, $b$, $c$ and $d$ are integers. The value of $\frac{b+c}{a+d}$ is ________.
Need Expert Advice?
More Questions from NEET

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App