The power of a crane, which lifts a mass of $1000 \text{ kg}$ to a height of $20 \text{ m}$ in $10 \text{ s}$ is :
($g = 9.8 \text{ m/s}^2$)
The problem asks for the power of a crane based on the mass it lifts, the height it lifts it to, and the time taken. We are given:
Power is the rate at which work is done. First, we calculate the work done by the crane in lifting the mass against gravity.
The work done ($W$) is equal to the potential energy gained by the mass, calculated using the formula:
$W = mgh$
Substituting the given values:
$W = (1000 \text{ kg}) \times (9.8 \text{ m/s}^2) \times (20 \text{ m})$
$W = 196000 \text{ J}$
Power ($P$) is calculated by dividing the work done by the time taken:
$P = \frac{W}{t}$
Substituting the calculated work and given time:
$P = \frac{196000 \text{ J}}{10 \text{ s}}$
$P = 19600 \text{ W}$
The options are given in kilowatts (kW). To convert watts to kilowatts, we divide by 1000:
$P = \frac{19600 \text{ W}}{1000 \text{ W/kW}}$
$P = 19.6 \text{ kW}$
Therefore, the power of the crane is $19.6 \text{ kW}$.
The following plots show variation of velocity ($v$) with time ($t$) of a ball thrown vertically upward, and falling back. Which of the following plots is/are correct?
A thin wire of length 'L' and linear mass density 'm' is bent into a circular ring (in x-y plane) with centre 'C' as shown in figure. The moment of inertia of the ring about an axis yy' (tangent in the plane) will be :
A frictionless circular wire of unit radius is fixed on the horizontal plane. Two point particles of unit mass start moving simultaneously from point $A \left( \theta = \frac{\pi}{2} \right)$ with identical uniform angular speeds in opposite directions, and meet again at point $B \left( \theta = -\frac{\pi}{2} \right)$. During this time, which of the following figures schematically represent the magnitude of the total linear momentum $\vec{P}$ of the system, as a function of $\theta$?

Suppose there is a uniform circular disc of mass $M \text{ kg}$ and radius $r \text{ m}$ shown in figure. The shaded regions are cut out from the disc. The moment of inertia of the remainder about the axis $A$ of the disc is given by $\frac{x}{256} M r^2$. The value of $x$ is ________.
