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Question

The amount of work done to raise a mass 'm' from the surface of the Earth to a height equal to the radius of the Earth 'R', will be :

This question was previously asked in
NEET UG Re-Exam 2026 Question Paper (21-Jun-2026)
The correct answer is
$\frac{mgR}{2}$

Calculating Work Done Against Gravity

The work done to move an object against a conservative force, like gravity, is equal to the change in its potential energy.

Potential Energy Formula

The gravitational potential energy ($U$) of a mass ($m$) at a distance ($r$) from the center of the Earth (mass $M$) is given by:

$U = -\frac{GMm}{r}$

Where $G$ is the gravitational constant.

Initial and Final States

  • Initial State: At the Earth's surface, the distance from the center is $r_1 = R$. The initial potential energy ($U_1$) is:

    $U_1 = -\frac{GMm}{R}$

  • Final State: The mass is raised to a height $R$ above the surface. The final distance from the center is $r_2 = R + R = 2R$. The final potential energy ($U_2$) is:

    $U_2 = -\frac{GMm}{2R}$

Work Done Calculation

The work done ($W$) is the change in potential energy:

$W = \Delta U = U_2 - U_1$

$W = \left(-\frac{GMm}{2R}\right) - \left(-\frac{GMm}{R}\right)$

$W = -\frac{GMm}{2R} + \frac{GMm}{R}$

$W = \frac{GMm}{R} \left(1 - \frac{1}{2}\right)$

$W = \frac{GMm}{2R}$

Relating to Surface Gravity

At the Earth's surface, the acceleration due to gravity is $g$. The force of gravity is $mg$. This force is also given by Newton's law of gravitation:

$mg = \frac{GMm}{R^2}$

From this, we can express $GM$ as:

$GM = gR^2$

Final Work Done Expression

Substitute $GM = gR^2$ into the work done equation:

$W = \frac{(gR^2)m}{2R}$

$W = \frac{mgR}{2}$

Therefore, the work done to raise the mass is $\frac{mgR}{2}$.

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