For a travelling harmonic wave $y(x, t) = 2.0 \cos 2\pi(10 t - 0.0080 x + 0.35)$, where $x$ and $y$ are in cm and $t$ in s. The phase difference between oscillatory motion of two points separated by a distance of $0.5 \text{ m}$ is :
The equation for the travelling harmonic wave is given as:
$y(x, t) = 2.0 \cos 2\pi(10 t - 0.0080 x + 0.35)$
In this equation, $x$ and $y$ are in centimeters (cm), and $t$ is in seconds (s).
The phase of the wave at any point $x$ and time $t$ is the argument of the cosine function:
$\Phi(x, t) = 2\pi(10 t - 0.0080 x + 0.35)$
The phase difference $\Delta \Phi$ between two points $x_1$ and $x_2$ at the same time $t$ is calculated as:
$\Delta \Phi = \Phi(x_2, t) - \Phi(x_1, t)$
Substituting the expression for phase:
$\Delta \Phi = \left[ 2\pi(10 t - 0.0080 x_2 + 0.35) \right] - \left[ 2\pi(10 t - 0.0080 x_1 + 0.35) \right]$
Simplify the expression by canceling common terms:
$\Delta \Phi = 2\pi [ (10 t - 0.0080 x_2 + 0.35) - (10 t - 0.0080 x_1 + 0.35) ]$
$\Delta \Phi = 2\pi [ -0.0080 x_2 + 0.0080 x_1 ]$
Factor out the common term $0.0080$:
$\Delta \Phi = 2\pi \times 0.0080 (x_1 - x_2)$
The distance between the two points is given as $0.5 \text{ m}$. Since the variable $x$ in the wave equation is in centimeters, we must convert the distance to centimeters:
$\Delta x = x_1 - x_2 = 0.5 \text{ m} \times \frac{100 \text{ cm}}{1 \text{ m}} = 50 \text{ cm}$
Now substitute the distance $\Delta x$ into the phase difference formula. We consider the magnitude of the phase difference:
$|\Delta \Phi| = |2\pi \times 0.0080 \times \Delta x|$
$|\Delta \Phi| = 2\pi \times 0.0080 \times 50$
Calculate the product:
$|\Delta \Phi| = 2\pi \times 0.4$
$|\Delta \Phi| = 0.8\pi \text{ rad}$
The phase difference between the two points separated by $0.5 \text{ m}$ is $0.8\pi$ radians.
A simple pendulum has a bob with mass $m$ and charge $q$. The pendulum string has negligible mass. When a uniform and horizontal electric field $\vec{E}$ is applied, the tension in the string changes. The final tension in the string, when pendulum attains an equilibrium position is _________.
(g: acceleration due to gravity)
In an open organ pipe $\nu_3$ and $\nu_6$ are $3^{\text{rd}}$ and $6^{\text{th}}$ harmonic frequencies, respectively. If $\nu_6 - \nu_3 = 2200 \text{ Hz}$ then length of the pipe is _________ mm.
(Take velocity of sound in air is $330 \text{ m/s}$.)