Given Electrical Parameters
The problem provides the following values:
- Battery Electromotive Force (emf), $\mathcal{E} = 12 \text{ V}$
- Internal Resistance, $r = 2 \ \Omega$
- Circuit Current, $I = 0.6 \text{ A}$
Formula for Terminal Voltage
The terminal voltage ($V_T$) of a battery is the actual voltage across its terminals when current is flowing. It can be calculated using the formula:
$ V_T = \mathcal{E} - Ir $
Where:
- $V_T$ is the terminal voltage
- $\mathcal{E}$ is the battery emf
- $I$ is the current flowing through the circuit
- $r$ is the internal resistance of the battery
Calculation of Terminal Voltage
Substitute the given values into the formula:
$ V_T = 12 \text{ V} - (0.6 \text{ A} \times 2 \ \Omega) $
First, calculate the voltage drop across the internal resistance:
$ I \times r = 0.6 \text{ A} \times 2 \ \Omega = 1.2 \text{ V} $
Now, subtract this voltage drop from the battery's emf:
$ V_T = 12 \text{ V} - 1.2 \text{ V} $
$ V_T = 10.8 \text{ V} $
Result
The terminal voltage of the battery is $10.8 \text{ V}$.
Similar Questions
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Important Questions from Electricity and Magnetism
- The electric current in the circuit is given as $i = i_o(t/T)$. The r.m.s current for the period $t = 0$ to $t = T$ is ________.
- In the potentiometer, when the cell in the secondary circuit is shunted with $4\text{ }\Omega$ resistance, the balance is obtained at the length $120\text{ cm}$ of wire. Now when the same cell is shunted with $12\text{ }\Omega$ resistance, the balance is shifted to a length of $180\text{ cm}$. The internal resistance of cell is ________$\Omega$
- The electric field of an electromagnetic wave travelling through a medium is given by $\vec{E}(x,t) = 25 \sin(2.0 \times 10^{15} t - 10^7 x) \hat{n}$
then the refractive index of the medium is ________.
(All given measurement are in SI units) Three long straight wires carrying current are arranged mutually parallel as shown in the figure. The force experienced by $15 \text{ cm}$ length of wire $Q$ is________.
$(\mu_o = 4\pi \times 10^{-7} \text{ T.m/A})$- For the two cells having same EMF $E$ and internal resistance $r$, the current passing through the external resistor $6\text{ }\Omega$ is same when both the cells are connected either in parallel or in series. The value of internal resistance $r$ is ________$\Omega$.
