
For a simple pendulum undergoing Simple Harmonic Motion (SHM), the kinetic energy ($K.E.$) varies cyclically with time ($t$). Key characteristics of this variation are:
The correct graph representing $K.E.$ versus $t$ must satisfy these conditions:
Considering these points, if the pendulum starts at an extreme position ($t=0$), its $K.E.$ is $0$. It increases to a maximum at $t=T/4$ (mean position), decreases to $0$ at $t=T/2$ (other extreme), increases to a maximum again at $t=3T/4$, and returns to $0$ at $t=T$. Option B accurately displays this behavior, showing a wave that starts at zero, rises to a peak, falls back to zero, and repeats this pattern, staying entirely within the non-negative domain and exhibiting the required periodicity.
For a travelling harmonic wave $y(x, t) = 2.0 \cos 2\pi(10 t - 0.0080 x + 0.35)$, where $x$ and $y$ are in cm and $t$ in s. The phase difference between oscillatory motion of two points separated by a distance of $0.5 \text{ m}$ is :
A particle is subjected to two simple harmonic motions as :
$x_1 = \sqrt{7} \sin 5t \text{ cm}$ and $x_2 = 2\sqrt{7} \sin \left(5t + \frac{\pi}{3}\right) \text{ cm}$
where x is displacement and t is time in seconds. The maximum acceleration of the particle is $x \times 10^{-2} \text{ ms}^{-2}$. The value of x is :