The problem asks us to find the distance between the Sun and the Earth using a new unit system where the speed of light is considered unity (1). We are given the time it takes for light to travel this distance.
First, we need to express the total time in a single unit, preferably seconds, to be consistent with standard calculations.
$t = (6 \text{ minutes} \times 60 \frac{\text{seconds}}{\text{minute}}) + 40 \text{ seconds}$
$t = 360 \text{ seconds} + 40 \text{ seconds}$
$t = 400 \text{ seconds}$
We use the fundamental relationship between distance, speed, and time: Distance = Speed × Time.
In this specific problem:
Therefore, the distance ($d$) is:
$d = c \times t$
$d = 1 \times 400 \text{ seconds}$
$d = 400$
Since the speed of light is taken as 1 unit of distance per unit of time (here, seconds), the distance calculated is in these new units. The unit would effectively be 'light-seconds'.
The distance between the Sun and the Earth, in the new unit system where the speed of light is unity, is 400 units (or 400 light-seconds).
| List - I | List - II |
| A. Meter (L) | I. $\sqrt{\frac{hc}{G}}$ |
| B. Second (S) | II. $\sqrt{\frac{Gh}{c^{5}}}$ |
| C. Kilogram (M) | III. $\sqrt{\frac{K^{2}L^{2}c^{3}}{Gh}}$ |
| D. Kelvin (K) | IV. $\sqrt{\frac{Gh}{c^{3}}}$ |