To determine the dimensions of the expression $\sigma_s k_B^{-1} b$, we first need the dimensions of each constant involved:
Now, we combine the dimensions of these constants according to the expression $\sigma_s k_B^{-1} b$. We substitute the dimensions of each term:
$ [\sigma_s k_B^{-1} b] = [\sigma_s] \times [k_B^{-1}] \times [b] $
First, find the dimensions of $k_B^{-1}$:
$ [k_B^{-1}] = \left( [M L^2 T^{-2} K^{-1}] \right)^{-1} = [M^{-1} L^{-2} T^{2} K^{1}] $
Next, substitute all dimensions into the expression:
$ [\sigma_s k_B^{-1} b] = [M T^{-3} K^{-4}] \times [M^{-1} L^{-2} T^{2} K^{1}] \times [L K] $
Combine the powers for each dimension (Mass M, Length L, Time T, Temperature K):
$ [\sigma_s k_B^{-1} b] = [M^{1 + (-1)}] [L^{0 + (-2) + 1}] [T^{-3 + 2}] [K^{-4 + 1 + 1}] $ $ [\sigma_s k_B^{-1} b] = [M^{0}] [L^{-1}] [T^{-1}] [K^{-2}] $
Simplifying, the dimensions are $[L^{-1} T^{-1} K^{-2}]$.
| List - I | List - II |
| A. Meter (L) | I. $\sqrt{\frac{hc}{G}}$ |
| B. Second (S) | II. $\sqrt{\frac{Gh}{c^{5}}}$ |
| C. Kilogram (M) | III. $\sqrt{\frac{K^{2}L^{2}c^{3}}{Gh}}$ |
| D. Kelvin (K) | IV. $\sqrt{\frac{Gh}{c^{3}}}$ |