Statement I : A satellite is moving around earth in the orbit very close to the earth surface. The time period of revolution of satellite depends upon the density of earth.
Statement II : The time period of revolution of the satellite is $T = 2\pi \sqrt{\frac{R_e}{g}}$ (for satellite very close to the earth surface), where $R_e$ radius of earth and g acceleration due to gravity.
In the light of the above statements, choose the correct answer from the options given below :
For a satellite orbiting very close to the Earth's surface, the orbital radius $r$ is approximately equal to the Earth's radius $R_e$. The time period $T$ is given by the formula:
$T = 2\pi \sqrt{\frac{r^3}{GM_e}}$
where $M_e$ is the mass of the Earth and $G$ is the gravitational constant.
We know the acceleration due to gravity at the surface is $g = \frac{GM_e}{R_e^2}$, which implies $GM_e = gR_e^2$. Substituting this into the time period formula for $r \approx R_e$:
$T \approx 2\pi \sqrt{\frac{R_e^3}{gR_e^2}} = 2\pi \sqrt{\frac{R_e}{g}}$
Now, let's express $g$ in terms of Earth's density ($\rho_e$). The mass of the Earth is $M_e = \rho_e \times (\frac{4}{3}\pi R_e^3)$.
So, $g = \frac{G(\rho_e \frac{4}{3}\pi R_e^3)}{R_e^2} = \frac{4}{3}\pi G \rho_e R_e$.
Substituting this expression for $g$ back into the time period formula:
$T \approx 2\pi \sqrt{\frac{R_e}{\frac{4}{3}\pi G \rho_e R_e}} = 2\pi \sqrt{\frac{3}{4\pi G \rho_e}}$
This derivation shows that the time period $T$ is inversely proportional to the square root of the Earth's density ($\rho_e$). Therefore, Statement I is true.
Statement II provides the formula $T = 2\pi \sqrt{\frac{R_e}{g}}$ for a satellite very close to the Earth's surface.
As derived above, this formula is an approximation obtained by setting the orbital radius $r$ equal to the Earth's radius $R_e$ in the general time period equation $T = 2\pi \sqrt{\frac{r^3}{GM_e}}$.
However, for any satellite in orbit, the orbital radius $r$ must be strictly greater than the Earth's radius $R_e$ ($r > R_e$). Even for orbits "very close" to the surface, $r$ is slightly larger than $R_e$. Using $R_e$ directly instead of $r$ makes the formula an approximation, not a strictly accurate representation for an orbit.
Because the formula uses $R_e$ instead of the actual orbital radius $r$, it is considered technically inaccurate. Therefore, Statement II is false.
Based on the analysis, Statement I is true, and Statement II is false.
The correct option is: Statement I is true but Statement II is false.
A cylindrical tube AB of length $l$, closed at both ends contains an ideal gas of 1 mol having molecular weight $M$. The tube is rotated in a horizontal plane with constant angular velocity $\omega$ about an axis perpendicular to AB and passing through the edge at end A, as shown in the figure. If $P_A$ and $P_B$ are the pressures at $A$ and $B$ respectively, then
(Consider the temperature is same at all points in the tube)

A uniform bar of length 12 cm and mass $20m$ lies on a smooth horizontal table. Two point masses $m$ and $2m$ are moving in opposite directions with same speed of $v$ and in the same plane as the bar, as shown in figure. These masses strike the bar simultaneously and get stuck to it. After collision the entire system is rotating with angular frequency $\omega$. The ratio of $v$ and $\omega$ is :
Match the LIST-I with LIST-II
| List-I: | List-II: |
| A. Magnetic induction | I. $[M L T^{-2} A^{-2}]$ |
| B. Magnetic flux | II. $[M L^2 T^{-2} A^{-2}]$ |
| C. Magnetic permeability | III. $[M L^0 T^{-2} A^{-1}]$ |
| D. Self inductance | IV. $[M L^2 T^{-2} A^{-1}]$ |
Choose the correct answer from the options given below:
A cylindrical tube AB of length $l$, closed at both ends contains an ideal gas of 1 mol having molecular weight $M$. The tube is rotated in a horizontal plane with constant angular velocity $\omega$ about an axis perpendicular to AB and passing through the edge at end A, as shown in the figure. If $P_A$ and $P_B$ are the pressures at $A$ and $B$ respectively, then
(Consider the temperature is same at all points in the tube)
