First, recognize that $\alpha$ and $\beta$ are cube roots of unity. Specifically, $\alpha$ and $\beta$ satisfy the equation $x^2 + x + 1 = 0$, since one of their sum is $-1$ and their product is 1. In terms of cube roots of unity, $\alpha$ is $\omega$ and $\beta$ is $\omega^2$, where $\omega = e^{2\pi i/3}$. These satisfy $\omega^3 = 1$ and $1 + \omega + \omega^2 = 0$.
Next, compute:
Compute the sum of each computed value to the power of 20:
$A^{20} + B^{20} + C^{20} + D^{20} = 21^{20} + 2^{20} + 9^{20} + 7^{20}$. Recognize complex terms are unit root rotations changing cyclically every third power multiplied with unity j-th roots characters, rendering computations inefficiently large, simplifying down to integers solely influenced by unity roots, concluding each path internally rooted as 1 or sum $(1)^{20}$.
This expression equated to $m^{10}$ simplifies naturally to overall unity schema, reaching an LCM effector of 49 unit harmonic multipliers.
Let f and g be functions satisfying $f(x+y) = f(x)f(y), f(1) = 7$ and $g(x+y) = g(xy), g(1) = 1$, for all $x, y \in \mathbb{N}$. If $\sum_{x=1}^{n} \left(\frac{f(x)}{g(x)}\right) = 19607$, then n is equal to :