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Question

A cylindrical tube AB of length $l$, closed at both ends contains an ideal gas of 1 mol having molecular weight $M$. The tube is rotated in a horizontal plane with constant angular velocity $\omega$ about an axis perpendicular to AB and passing through the edge at end A, as shown in the figure. If $P_A$ and $P_B$ are the pressures at $A$ and $B$ respectively, then
(Consider the temperature is same at all points in the tube)

The correct answer is
$P_B = P_A$

To solve this problem, we need to analyze the effect of rotation on the pressure distribution in the cylindrical tube containing an ideal gas. The tube is rotated with an angular velocity \omega around an axis passing through point A. Let's break down the steps:

  1. The tube is horizontal and closed at both ends, with 1 mol of ideal gas inside.
  2. The rotation causes the gas molecules to experience a centrifugal force, which acts outward from the axis of rotation (point A in this case). However, the axis of rotation is perpendicular to the tube length, AB.
  3. The centrifugal force per unit volume on the gas can be expressed as F = \rho \omega^2 r, where \rho is the density of the gas, and r is the distance from the axis of rotation.
  4. At point A, r=0, and at point B, r=l. However, since the forces act perpendicularly, the pressure distribution due to centrifugal force does not affect the gas along the tube length.
  5. The temperature is constant at all points; thus, according to the ideal gas law and no difference in forces acting along the tube's length direction, the pressures at both ends remain equal.

Since the centrifugal force does not contribute to any pressure gradient along the length of the tube, the pressure at point B, P_B, equals the pressure at point A, P_A.

Therefore, the correct answer is:

P_B = P_A
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Similar Questions

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Important Questions from Mechanics

  1. The escape velocity from a spherical planet A is 10 km/s. The escape velocity from another planet B whose density and radius are 10% of those of planet A, is _________ m/s.
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  3. A circular disc has radius $R_1$ and thickness $T_1$. Another circular disc made of the same material has radius $R_2$ and thickness $T_2$. If the moment of inertia of both discs are same and $\frac{R_1}{R_2} = 2$ then $\frac{T_1}{T_2} = \frac{1}{\alpha}$. The value of $\alpha$ is _________.
  4. Given below are two statements :
    Statement I : A satellite is moving around earth in the orbit very close to the earth surface. The time period of revolution of satellite depends upon the density of earth.
    Statement II : The time period of revolution of the satellite is $T = 2\pi \sqrt{\frac{R_e}{g}}$ (for satellite very close to the earth surface), where $R_e$ radius of earth and g acceleration due to gravity.
    In the light of the above statements, choose the correct answer from the options given below :
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