P can finish a work in 18 days. When he had worked for 5 days, Q joined him. If both of them together completed the remaining work in \(\frac{13}{5} \) days, then in how many days can Q alone finish \(66\frac{2}{3} \) % of the same work?
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This problem involves concepts of work and time, specifically how individuals (P and Q) complete a task alone and when working together. We are given the time P takes to complete the entire work, the duration P works alone, the time P and Q work together on the remaining part, and we need to find the time Q takes to complete a specific percentage of the work alone.
P can finish the entire work in 18 days. This means P's daily work rate is \( \frac{1}{18} \) of the total work per day.
P worked alone for 5 days. The amount of work completed by P in these 5 days is:
Work done by P in 5 days = Work rate of P \(\times\) Number of days worked
Work done by P in 5 days = \( \frac{1}{18} \times 5 = \frac{5}{18} \) of the total work.
After P worked for 5 days, the amount of work remaining is the total work minus the work done by P:
Remaining Work = Total Work - Work done by P
Remaining Work = \( 1 - \frac{5}{18} = \frac{18 - 5}{18} = \frac{13}{18} \) of the total work.
The remaining \( \frac{13}{18} \) of the work was completed by both P and Q working together in \( \frac{13}{5} \) days.
Their combined daily work rate is the remaining work divided by the time taken to complete it:
Combined Work Rate of P and Q = \( \frac{\text{Remaining Work}}{\text{Time taken by P and Q together}} \)
Combined Work Rate of P and Q = \( \frac{\frac{13}{18}}{\frac{13}{5}} = \frac{13}{18} \times \frac{5}{13} = \frac{5}{18} \) of the total work per day.
We know P's daily work rate is \( \frac{1}{18} \) and the combined daily work rate of P and Q is \( \frac{5}{18} \).
Q's daily work rate can be found by subtracting P's work rate from the combined work rate:
Q's Work Rate = Combined Work Rate of P and Q - P's Work Rate
Q's Work Rate = \( \frac{5}{18} - \frac{1}{18} = \frac{5-1}{18} = \frac{4}{18} = \frac{2}{9} \) of the total work per day.
First, let's convert the percentage to a fraction:
\( 66\frac{2}{3} \% = \frac{(66 \times 3) + 2}{3} \% = \frac{198 + 2}{3} \% = \frac{200}{3} \% \)
To convert percentage to fraction, divide by 100: \( \frac{200}{3} \times \frac{1}{100} = \frac{200}{300} = \frac{2}{3} \).
So, we need to find the time Q takes to finish \( \frac{2}{3} \) of the same work.
Q's daily work rate is \( \frac{2}{9} \) of the work. This means Q takes \( \frac{1}{2/9} = \frac{9}{2} \) days to complete the entire work (100%).
The time Q takes to complete \( \frac{2}{3} \) of the work is:
Time taken by Q = \( \frac{\text{Fraction of work to be done}}{\text{Q's daily work rate}} \)
Time taken by Q = \( \frac{\frac{2}{3}}{\frac{2}{9}} = \frac{2}{3} \times \frac{9}{2} = \frac{18}{6} = 3 \) days.
Therefore, Q alone can finish \( 66\frac{2}{3} \) % of the same work in 3 days.
| Entity | Information |
|---|---|
| P's total time | 18 days |
| P's daily rate | \( \frac{1}{18} \) work/day |
| P works alone | 5 days |
| Work done by P | \( 5 \times \frac{1}{18} = \frac{5}{18} \) |
| Remaining work | \( 1 - \frac{5}{18} = \frac{13}{18} \) |
| Time P & Q together | \( \frac{13}{5} \) days |
| Combined rate (P+Q) | \( \frac{13/18}{13/5} = \frac{5}{18} \) work/day |
| Q's daily rate | \( \frac{5}{18} - \frac{1}{18} = \frac{4}{18} = \frac{2}{9} \) work/day |
| Percentage for Q | \( 66\frac{2}{3} \% = \frac{2}{3} \) |
| Time for Q (2/3 work) | \( \frac{2/3}{2/9} = \frac{2}{3} \times \frac{9}{2} = 3 \) days |
The final answer is 3 days.
| Concept | Formula/Explanation |
|---|---|
| Work Rate | If a person completes a work in 'n' days, their daily work rate is \( \frac{1}{n} \) of the work per day. |
| Work Done | Work Done = Work Rate \(\times\) Time |
| Time Taken | Time Taken = \( \frac{\text{Total Work}}{\text{Work Rate}} \). If doing a fraction of work, Time = \( \frac{\text{Fraction of Work}}{\text{Work Rate}} \). |
| Combined Work Rate | If A's rate is \(R_A\) and B's rate is \(R_B\), their combined rate is \(R_A + R_B\). |
| Remaining Work | Remaining Work = Total Work - Work Done |
Work and Time problems are common in quantitative aptitude sections of various exams. They typically involve individuals or machines working at different rates to complete a task. The key is to convert the time taken to complete the whole work into a work rate (fraction of work done per unit time, usually a day).
Understanding these fundamental principles helps in solving various complex Work and Time scenarios effectively.
A and B together can complete a certain work in 20 days whereas B and C together can complete it in 24 days. If A is twice as good a workman as C, then in what time will B alone do 40% of the same work?
14 men can complete a work in 15 days. If 21 men are employed, then in how many days will they complete the same work?
A can do a certain work in 15 days, while B can do the same work in 21 days. If they work together, then in how many days will the same work be completed?
To do a certain work, A and B work on alternate days with B beginning the work on the first day. A alone can complete the same work in 24 days. If the work gets completed in \(11 \frac{1}{3}\) days, then B alone can complete \(\rm \frac{7}{9}^{th}\) part of the original work in:
Two men and 7 women can complete a work in 28 days whereas 6 men and 16 women can do the same work in 11 days. In how many days can 7 men complete the same work?