P can finish a work in 18 days. When he had worked for 5 days, Q joined him. If both of them together completed the remaining work in \(\frac{13}{5} \) days, then in how many days can Q alone finish \(66\frac{2}{3} \) % of the same work?
3
This problem involves concepts of work and time, specifically how individuals (P and Q) complete a task alone and when working together. We are given the time P takes to complete the entire work, the duration P works alone, the time P and Q work together on the remaining part, and we need to find the time Q takes to complete a specific percentage of the work alone.
P can finish the entire work in 18 days. This means P's daily work rate is \( \frac{1}{18} \) of the total work per day.
P worked alone for 5 days. The amount of work completed by P in these 5 days is:
Work done by P in 5 days = Work rate of P \(\times\) Number of days worked
Work done by P in 5 days = \( \frac{1}{18} \times 5 = \frac{5}{18} \) of the total work.
After P worked for 5 days, the amount of work remaining is the total work minus the work done by P:
Remaining Work = Total Work - Work done by P
Remaining Work = \( 1 - \frac{5}{18} = \frac{18 - 5}{18} = \frac{13}{18} \) of the total work.
The remaining \( \frac{13}{18} \) of the work was completed by both P and Q working together in \( \frac{13}{5} \) days.
Their combined daily work rate is the remaining work divided by the time taken to complete it:
Combined Work Rate of P and Q = \( \frac{\text{Remaining Work}}{\text{Time taken by P and Q together}} \)
Combined Work Rate of P and Q = \( \frac{\frac{13}{18}}{\frac{13}{5}} = \frac{13}{18} \times \frac{5}{13} = \frac{5}{18} \) of the total work per day.
We know P's daily work rate is \( \frac{1}{18} \) and the combined daily work rate of P and Q is \( \frac{5}{18} \).
Q's daily work rate can be found by subtracting P's work rate from the combined work rate:
Q's Work Rate = Combined Work Rate of P and Q - P's Work Rate
Q's Work Rate = \( \frac{5}{18} - \frac{1}{18} = \frac{5-1}{18} = \frac{4}{18} = \frac{2}{9} \) of the total work per day.
First, let's convert the percentage to a fraction:
\( 66\frac{2}{3} \% = \frac{(66 \times 3) + 2}{3} \% = \frac{198 + 2}{3} \% = \frac{200}{3} \% \)
To convert percentage to fraction, divide by 100: \( \frac{200}{3} \times \frac{1}{100} = \frac{200}{300} = \frac{2}{3} \).
So, we need to find the time Q takes to finish \( \frac{2}{3} \) of the same work.
Q's daily work rate is \( \frac{2}{9} \) of the work. This means Q takes \( \frac{1}{2/9} = \frac{9}{2} \) days to complete the entire work (100%).
The time Q takes to complete \( \frac{2}{3} \) of the work is:
Time taken by Q = \( \frac{\text{Fraction of work to be done}}{\text{Q's daily work rate}} \)
Time taken by Q = \( \frac{\frac{2}{3}}{\frac{2}{9}} = \frac{2}{3} \times \frac{9}{2} = \frac{18}{6} = 3 \) days.
Therefore, Q alone can finish \( 66\frac{2}{3} \) % of the same work in 3 days.
| Entity | Information |
|---|---|
| P's total time | 18 days |
| P's daily rate | \( \frac{1}{18} \) work/day |
| P works alone | 5 days |
| Work done by P | \( 5 \times \frac{1}{18} = \frac{5}{18} \) |
| Remaining work | \( 1 - \frac{5}{18} = \frac{13}{18} \) |
| Time P & Q together | \( \frac{13}{5} \) days |
| Combined rate (P+Q) | \( \frac{13/18}{13/5} = \frac{5}{18} \) work/day |
| Q's daily rate | \( \frac{5}{18} - \frac{1}{18} = \frac{4}{18} = \frac{2}{9} \) work/day |
| Percentage for Q | \( 66\frac{2}{3} \% = \frac{2}{3} \) |
| Time for Q (2/3 work) | \( \frac{2/3}{2/9} = \frac{2}{3} \times \frac{9}{2} = 3 \) days |
The final answer is 3 days.
| Concept | Formula/Explanation |
|---|---|
| Work Rate | If a person completes a work in 'n' days, their daily work rate is \( \frac{1}{n} \) of the work per day. |
| Work Done | Work Done = Work Rate \(\times\) Time |
| Time Taken | Time Taken = \( \frac{\text{Total Work}}{\text{Work Rate}} \). If doing a fraction of work, Time = \( \frac{\text{Fraction of Work}}{\text{Work Rate}} \). |
| Combined Work Rate | If A's rate is \(R_A\) and B's rate is \(R_B\), their combined rate is \(R_A + R_B\). |
| Remaining Work | Remaining Work = Total Work - Work Done |
Work and Time problems are common in quantitative aptitude sections of various exams. They typically involve individuals or machines working at different rates to complete a task. The key is to convert the time taken to complete the whole work into a work rate (fraction of work done per unit time, usually a day).
Understanding these fundamental principles helps in solving various complex Work and Time scenarios effectively.
To do a certain work, A and B work on alternate days with B beginning the work on the first day. A alone can complete the same work in 24 days. If the work gets completed in \(11 \frac{1}{3}\) days, then B alone can complete \(\rm \frac{7}{9}^{th}\) part of the original work in:
R, S and T can finish a work in 20, 15 and 10 days, respectively. R works on all days and S and T work on alternate days with T starting the work on the first day. In how many days is the work finished?
A can do \(1 \over 3\) of a piece of work in 32 days, B can do \(37{1 \over 2}\)% of the same work in 24 days, while C can do 60% of the same work in 48 days. B and C together started and worked for x days. After x days, B left the work and A joined C and both completed the remaining work in (x + 8) days. If the ratio of the work done by (B + C) together to the work done by (A + C) together is 9 ∶ 11, then what fraction of the same work can be completed by C alone in 3.5x days?
A group of college students had decided to complete a project in 10 days. As 2 students dropped out every day, the project got completed at the end of the 15th day. The number of students at the beginning of the project was:
A group of men decided to do a job in 13 days but 9 men left the work after each day. The work, as a result, got completed in 16 days. How many men were initially in the group?
Three men and 4 women can do a piece of work in 7 days, whereas 2 men and 1 woman can do it in 14 days. Seven women will complete the same work in:
Five men can complete a work in 20 days. Ten women can complete the same work in 15 days. Two men and six women started working together. After 5 days, three women left the work a new man joined the work. The group continued working together till the end of the work. In how many days will they be able to do the remaining work?
4 men and 5 women can complete a work in 15 days, whereas 9 men and 6 women can do it in 10 days. To complete the same work in 7 days, how many women should assist 4 men?
Four men and 6 women can complete a certain piece of work in 5 days whereas three men and 4 women can complete it in 7 days. How many men should assist 25 women to complete \(2\frac{1}{2}\) times the same work in 5 days?
A can complete a work in 60 days. B is 25% more efficient than A. They work together for 15 days. C alone completes the remaining work in 14 days. B and C together will complete \(\frac{5}{8}\)th part of the original work in:
A man completes 7/8 of a job in 21 days. How many more days will it take him to finish the job if quantum of work further increased by 50%?
24 men and 12 women can do a piece of work in 30 days. In how many days can 12 men and 24 women do the same piece of work?
A and B together can do a piece of work in 4 days, B and C can do it in 6 days, A and C can do it in 8 days. Then A, B and C together can do the same work in :-
A can complete 50% of a work in 9 days and B can do 25% of the work in 9 days, if they work alone. If they work together then how much work (in percentage) can be completed in 6 days?
A is thrice as good a workman as B. C alone takes 48 days to paint a house. All three A, B and C working together take 16 days to paint the house. It will take how many days for A alone to paint the house?