Three men and 4 women can do a piece of work in 7 days, whereas 2 men and 1 woman can do it in 14 days. Seven women will complete the same work in:
10 days
This problem involves calculating the time taken by a group of women to complete a certain amount of work, given information about the work rate of mixed groups of men and women. These types of problems are often solved by determining the individual efficiency of men and women.
We are given two scenarios:
We need to find out how many days 7 women will take to complete the same work.
Let's denote the work done by one man in one day as \(m\) and the work done by one woman in one day as \(w\). The total work is constant in all scenarios.
The total work done is the product of the number of workers, their individual efficiency, and the number of days they work.
From Scenario 1:
The work done by 3 men and 4 women in one day is \(3m + 4w\).
Since they complete the work in 7 days, the total work is \((3m + 4w) \times 7\).
Total Work \(W = 7(3m + 4w) = 21m + 28w\) (Equation 1)
From Scenario 2:
The work done by 2 men and 1 woman in one day is \(2m + w\).
Since they complete the work in 14 days, the total work is \((2m + w) \times 14\).
Total Work \(W = 14(2m + w) = 28m + 14w\) (Equation 2)
Since the total work \(W\) is the same in both scenarios, we can equate Equation 1 and Equation 2:
\(21m + 28w = 28m + 14w\)
Now, let's rearrange the terms to find the relationship between \(m\) and \(w\):
\(28w - 14w = 28m - 21m\)
\(14w = 7m\)
Dividing both sides by 7:
\(2w = m\)
This tells us that the work done by one man in a day is equal to the work done by two women in a day. In other words, one man is twice as efficient as one woman.
Now we can substitute the relationship \(m = 2w\) into either Equation 1 or Equation 2 to express the total work \(W\) entirely in terms of women's efficiency \(w\).
Using Equation 1:
\(W = 21m + 28w\)
\(W = 21(2w) + 28w\)
\(W = 42w + 28w\)
\(W = 70w\)
This means the total work is equivalent to 70 units of work, where each unit represents the work done by one woman in one day. We can call this 70 'woman-days' of work.
We want to find the time taken by 7 women to complete the total work \(W\). The work done by 7 women in one day is \(7w\).
The time taken is the total work divided by the work done per day by the group:
\text{Time} = \frac{\text{Total Work}}{\text{Work done by 7 women per day}}
\text{Time} = \frac{W}{7w}
Substitute \(W = 70w\):
\text{Time} = \frac{70w}{7w}
\text{Time} = \frac{70}{7}
\text{Time} = 10 \text{ days}
| Concept | Explanation |
|---|---|
| Efficiency | The amount of work done by a person or group in one unit of time. |
| Total Work | The entire task to be completed. It can be calculated as (Total Efficiency) \(\times\) (Time Taken). |
| Relationship between Workers | Often, the efficiency of different types of workers (like men vs. women) needs to be related to each other. |
| Combined Efficiency | The sum of the individual efficiencies of all workers in a group. |
| Time Taken | Calculated as Total Work / Combined Efficiency. |
Work problems often involve concepts like:
Understanding these concepts helps in solving various types of time and work problems, including those involving pipes and cisterns (where filling/emptying acts as 'work').
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