In the given figure AB is parallel to CD and AC is parallel to BD. If ∠EAC = 40°, ∠FDG = 55°, ∠HAB = x°, then what is the value of x? 
85°
Given:
∠EAC = 40°
∠FDG = 55°
∠HAB = x°
Formula Used:
Sum of angles on a straight line = 180°
Calculation:
As we know, when two parallel lines are intersected by another set of parallel lines, the angles formed are equal,
⇒ ∠CAB = ∠FDG = 55°
Now, the sum of angles on a straight line = 180°
⇒ ∠EAC + ∠CAB + ∠HAB = 180°
⇒ 40° + 55° + x° = 180°
⇒ x = 180° – 95° = 85°
∴ The value of x is 85°.
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