If two lines AB and CD intersect at O such that ∠AOC = 5 ∠AOD, then the four angles at O are
30°, 30°, 150°, 150°
When two lines intersect at a point, they form four angles around that point. These angles have specific relationships, such as forming linear pairs and being vertically opposite to each other. This problem involves finding the measures of these four angles given a relationship between two adjacent angles.
To solve this problem, we need to recall two important geometric concepts:
We are given two lines AB and CD that intersect at point O. The angles formed at O are \(\angle AOC\), \(\angle AOD\), \(\angle BOD\), and \(\angle BOC\).
We are given the relationship: \(\angle AOC = 5 \angle AOD\).
Let's denote \(\angle AOD\) as \(x\). According to the given information, \(\angle AOC = 5x\).
Angles \(\angle AOC\) and \(\angle AOD\) form a linear pair on the line CD (or AB). Therefore, their sum is \(180^\circ\).
\(\angle AOC + \angle AOD = 180^\circ\)
Substitute the expressions in terms of \(x\):
\(5x + x = 180^\circ\)
Combine the terms:
\(6x = 180^\circ\)
Solve for \(x\):
\(x = \frac{180^\circ}{6}\)
\(x = 30^\circ\)
Now that we have the value of \(x\), we can find the measures of \(\angle AOD\) and \(\angle AOC\):
Now we can find the measures of the other two angles using the property of vertically opposite angles:
The four angles formed at the intersection point O are:
Listing the four angles in numerical order gives: \(30^\circ, 30^\circ, 150^\circ, 150^\circ\).
| Angle | Relation | Measure |
|---|---|---|
| \(\angle AOD\) | Let it be \(x\) | \(30^\circ\) |
| \(\angle AOC\) | \(5 \angle AOD\) | \(150^\circ\) |
| \(\angle BOC\) | Vertically opposite to \(\angle AOD\) | \(30^\circ\) |
| \(\angle BOD\) | Vertically opposite to \(\angle AOC\) | \(150^\circ\) |
These angles \(30^\circ, 30^\circ, 150^\circ, 150^\circ\) correspond to one of the given options.
| Property | Description | Relationship |
|---|---|---|
| Linear Pair | Two adjacent angles on a straight line | Sum is \(180^\circ\) |
| Vertically Opposite Angles | Angles opposite at the intersection of two lines | Angles are equal |
| Angles Around a Point | Sum of all angles around a single point | Sum is \(360^\circ\) |
When lines intersect, they create pairs of angles with specific properties. Understanding these properties is crucial for solving geometry problems involving intersecting lines. Apart from linear pairs and vertically opposite angles, other angle relationships exist when parallel lines are involved, such as corresponding angles, alternate interior angles, and consecutive interior angles. However, for simple intersecting lines without parallelism, linear pairs and vertically opposite angles are the primary concepts.
Remember that the sum of all four angles around the intersection point O must be \(360^\circ\). Let's check our result: \(30^\circ + 150^\circ + 30^\circ + 150^\circ = 360^\circ\). This confirms our calculations are correct.
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