The locus of a point equidistant from two intersecting lines is
A pair of straight lines
The question asks us to find the locus of a point that is equidistant from two intersecting lines. The term 'locus' refers to the set of all points that satisfy a given condition.
In this specific case, the condition is that the distance from a point to the first line is equal to the distance from the same point to the second line.
Consider two lines, let's call them \(L_1\) and \(L_2\), that intersect at a point, say O.
These two lines divide the plane into four angles (two pairs of vertically opposite angles).
A point P is equidistant from \(L_1\) and \(L_2\) if the perpendicular distance from P to \(L_1\) is equal to the perpendicular distance from P to \(L_2\).
Geometrically, the set of points equidistant from two intersecting lines forms two straight lines. These lines are the bisectors of the angles formed by the two intersecting lines.
Let's visualize this:
These two angle bisector lines are perpendicular to each other and pass through the intersection point O of the original lines.
| Concept | Description |
|---|---|
| Locus | Set of points satisfying a condition. |
| Equidistant | Same distance from two or more objects. |
| Intersecting Lines | Lines that cross at a single point. |
| Angle Bisector | Locus of points equidistant from two rays forming an angle. |
Since the locus consists of two distinct straight lines (the angle bisectors), the correct description of this locus is "a pair of straight lines".
Let the equations of the two intersecting lines be \(a_1x + b_1y + c_1 = 0\) and \(a_2x + b_2y + c_2 = 0\). The equations of the angle bisectors (the locus of points equidistant from these lines) are given by:
\( \frac{a_1x + b_1y + c_1}{\sqrt{a_1^2 + b_1^2}} = \pm \frac{a_2x + b_2y + c_2}{\sqrt{a_2^2 + b_2^2}} \)
The \(\pm\) sign gives the equations of the two distinct angle bisectors, which form a pair of straight lines.
Based on the geometric properties and the algebraic representation, the locus of a point equidistant from two intersecting lines is a pair of straight lines.
| Locus Condition | Description of Locus |
|---|---|
| Equidistant from a fixed point | A circle (with the fixed point as center). |
| Equidistant from a fixed line | A pair of parallel lines (one on each side of the fixed line). If restricted to one side, it's a single parallel line. |
| Equidistant from two fixed points | The perpendicular bisector of the segment joining the two points. (A single straight line). |
| Equidistant from a fixed point and a fixed line (not passing through the point) | A parabola. |
| Equidistant from two intersecting lines | A pair of straight lines (the angle bisectors). |
The two angle bisectors of two intersecting lines are always perpendicular to each other. This is because they bisect angles that are supplementary. If the angles are \( \theta \) and \( 180^\circ - \theta \), the bisectors make angles of \( \theta/2 \) and \( (180^\circ - \theta)/2 = 90^\circ - \theta/2 \) with one of the original lines. The angle between the bisectors is the sum of these angles, \( \theta/2 + (90^\circ - \theta/2) = 90^\circ \).
The angle bisectors pass through the point of intersection of the original lines.

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