The measure of an angle for which the measure of the supplement is four times the measure of the complement is:
60°
This problem involves understanding the relationship between an angle and its supplementary and complementary angles. Let's break down the concepts:
The question states that the measure of the supplement of an angle is four times the measure of its complement. Let the measure of the angle be represented by the variable $x$.
According to the problem statement, we can write the equation:
Measure of Supplement = 4 × Measure of Complement
Using the expressions above, the equation becomes:
$$180^\circ - x = 4(90^\circ - x)$$
Now, we need to solve this algebraic equation for $x$. Let's follow the steps:
$$180^\circ - x = 4 \times 90^\circ - 4 \times x$$
$$180^\circ - x = 360^\circ - 4x$$
$$180^\circ - x + 4x = 360^\circ - 4x + 4x$$
$$180^\circ + 3x = 360^\circ$$
$$180^\circ + 3x - 180^\circ = 360^\circ - 180^\circ$$
$$3x = 180^\circ$$
$$x = \frac{180^\circ}{3}$$
$$x = 60^\circ$$
Let's check if the angle $x = 60^\circ$ satisfies the condition given in the question.
Now, let's see if the supplement ($120^\circ$) is four times the complement ($30^\circ$):
$$4 \times 30^\circ = 120^\circ$$
Since $120^\circ = 120^\circ$, our calculated value of $x = 60^\circ$ is correct.
The measure of the angle is $60^\circ$.
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