All Exams Test series for 1 year @ ₹349 only
Question

In a J-K FF, if J = Q and K = 1 (see figure). Assuming the flip flop was initially cleared and then clocked for 6 pulses, the sequence at the Q output will be :

This question was previously asked in
UGC NET 2023 Electronic Science Question Paper (13-Dec-2023) (Shift 1)
The correct answer is

010101

 Work out what the flip-flop does in each of its two possible states, and the pattern follows immediately.

The J-K rule is: J = K = 1 toggles, J = 0 with K = 1 resets, J = 1 with K = 0 sets, J = K = 0 holds. Here K is permanently 1 and J follows \(\overline{Q}\), so only two cases arise:

Present QJ = QKActionNext Q
011Toggle1
101Reset0

Both rows produce a change of state, by different routes: from 0 the flip-flop toggles to 1, and from 1 it is reset back to 0. The output therefore alternates on every clock edge, exactly as a plain toggle flip-flop would — the arrangement is a divide-by-two.

Reading off the sequence. The flip-flop starts cleared, so Q = 0, and the output then alternates:

\(0\rightarrow1\rightarrow0\rightarrow1\rightarrow0\rightarrow1\)

Sampling the Q output at six successive points beginning from the cleared state gives 010101 — option 4.

Why the other options are impossible. Every one of them contains two adjacent equal bits — 010000 has four zeros in a row, 011001 has a repeated 1 and a repeated 0, 010010 has two adjacent zeros. But the table above shows the output cannot stay put: whatever state it is in, the next clock changes it. Only an alternating pattern is possible, and option 4 is the only alternating sequence offered. That check alone settles the question without tracing a single pulse.

Why the feedback is redundant here. Tying J to \(\overline{Q}\) looks as though it should do something clever, but the two rows collapse to the same behaviour as simply tying J to 1. The circuit is a T flip-flop in disguise, and its output frequency is half the clock frequency — the building block of every binary counter.

One practical caution : feeding an output back to an input of the same flip-flop is safe only with an edge-triggered or master-slave device. A level-triggered latch would race around while the clock stayed high, toggling repeatedly and ending in an unpredictable state.

Hence, the sequence at Q is 010101.

Was this answer helpful?

Similar Questions

  1. Read the following statements :

    i. Gate is a combinational logic.
    ii. JK Flip-flop in toggle mode is not combinational logic.
    iii. MSJK FF suffers from race-around.
    iv. Counters are sequential circuits.

    Which is correct ?

  2. Which flip-flop can be used as latch ?

  3. Consider the following statements regarding registers and latches :

    (A) Registers are made of edge triggered flip-flops whereas latches are made from level triggered flip flops
    (B) Registers are temporary storage devices whereas latches are not
    (C) A latch employs cross coupled feed back connections
    (D) A register stores a binary word whereas a latch does not

    Choose the most appropriate answer from the options given below :

  4. The toggle condition appears in J-K flip-flop when

    A. J=1, K=1

    B. J=0, K=0

    C. J=0, K=1

    D. J=1, K=0

    E. J=0, K=1 and J=1, K=0

    Choose the correct answer from the options given below :

  5. Match List I with List II

    LIST I (Diagram)LIST II (Sequential Circuit)
    A. I.Edge triggered S-R flip flop
    B. II.D Flip flop to SR flip flop
    C. III.Gated Latch clocked flip flop
    D. IV.Gated D Latch

    Choose the correct answer from the options given below:

  6. The truth table of D flip-flop is given below:

    C  DQn+1
    OXQn (Last State)
    $\uparrow$00
    $\uparrow$11

    Choose exact characteristic equation based on above Truth Table

  7. Assertion (A) : Delay flip flop is used to store a single bit either 0 or 1.

    Reason (R) : It has only one input, when clock is high and D input is also high, the output resets.

  8. Assertion (A) : Asynchronous sequential circuit is also called event driven circuit.

    Reason (R) : Event driven circuit does not have clock to trigger change of state. The states are changed by the change in input signal of the previous stage.

    Select your answer using the codes given below.

  9. For the circuit shown below consider the two statements :

    Assertion (A) : The circuit is sequential.

    Reason (R) : There is a loop in circuit.

    Select your answer using the codes given below.

  10. Flip Flop can be used to make :

    (a) Latches  

     (b) Bounce-elimination switches   

    (c) ADDER   

    (d) Encoder

    Which of the statements given above are correct ?


Important Questions from Sequential Circuits

  1. The basic sequential logic building block in which the output follows the data input as long as the ENABLE input is active, is

  2. What can be the maximum clock frequency of a 10-bit ripple counter which will not cause a count to skip, considering 10 ns propagation delay for each of the edge-triggered flip flops?

  3. The output of a sequential circuit depends on

  4. The basic building block of a sequential logic circuit is

  5. A 4bit synchronous counter uses flip-flops with a propagation delay time of 25ns each. The maximum possible time required for change of state will be

Need Expert Advice?
Upcoming Exams
MH SET
October 25, 2026
CTET
December 12, 2026
Test Series
UGC NET img
Teaching
UGC NET (Paper 1) 2026 Mock Test Series
476 Tests 1 Tests Free
4.3(72)
English, Hindi

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App