This problem involves calculating the time taken by an individual (Baban) to complete a work, given information about the combined work rates of multiple people.
Let the rates of work for Athar, Baban, and Chetan be $R_A$, $R_B$, and $R_C$ respectively. The rate signifies the fraction of the work completed per day.
We have a system of three equations. Substitute the value of $R_C$ from the third equation into the first equation:
$ R_A = R_B + \frac{1}{50} $Now substitute this expression for $R_A$ into the second equation:
$ \left( R_B + \frac{1}{50} \right) + R_B = \frac{1}{10} $Simplify and solve for $R_B$:
$ 2 R_B + \frac{1}{50} = \frac{1}{10} $ $ 2 R_B = \frac{1}{10} - \frac{1}{50} $Find a common denominator (50) for the subtraction:
$ 2 R_B = \frac{5}{50} - \frac{1}{50} $ $ 2 R_B = \frac{4}{50} $ $ 2 R_B = \frac{2}{25} $ $ R_B = \frac{1}{25} $Baban's rate of work is $\frac{1}{25}$ of the work per day. The time taken by Baban alone is the reciprocal of his rate:
$ \text{Time for Baban} = \frac{1}{R_B} = \frac{1}{1/25} = 25 \text{ days} $A and B can do a piece of work in 18 days. B and C together can do it in 30 days. If A is twice as good a workman as C, find in how many days B alone can do the work?
Two men and 7 women can complete a work in 28 days, whereas 6 men and 16 women can do the same work in 11 days. In how many days will 5 men and 4 women, working together, complete the same work?
A man and a woman, working together can do a work in 66 days. The ratio of their working efficiencies is 3 ∶ 2. In how many days 6 men and 2 women together can do the same work?
Each one of five men independently can complete a work in 20 days. The work is started by one person. Next day one more person joins and every next day one more person joins. From the fifth day, five persons continued working as a team. In how many days, will the work be completed?
Numan does half the work as Gagan in 4/5 of the time. If together they take 16 days to complete a piece of work, then how long will it take Gagan to complete the work?