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Question

Athar can do a certain work in the same time in which Baban and Chetan together can do it. If Athar and Baban together could do it in 10 days and Chetan alone in 50 days, then Baban alone could do it in:

This question was previously asked in
SSC CGL 2025 Tier 1 Question Paper (25-Sep-2025) (Shift 3)
The correct answer is
25 days

Work and Time: Baban's Solo Duration Calculation

This problem involves calculating the time taken by an individual (Baban) to complete a work, given information about the combined work rates of multiple people.

Define Work Rates

Let the rates of work for Athar, Baban, and Chetan be $R_A$, $R_B$, and $R_C$ respectively. The rate signifies the fraction of the work completed per day.

Formulate Equations from the Problem Statement

  • "Athar can do a certain work in the same time in which Baban and Chetan together can do it." This means their rates are equal: $ R_A = R_B + R_C $
  • "Athar and Baban together could do it in 10 days." Their combined rate is the sum of their individual rates, and they complete the work in 10 days: $ R_A + R_B = \frac{1}{10} $
  • "Chetan alone in 50 days." Chetan's individual rate is: $ R_C = \frac{1}{50} $

Solve for Baban's Rate ($R_B$)

We have a system of three equations. Substitute the value of $R_C$ from the third equation into the first equation:

$ R_A = R_B + \frac{1}{50} $

Now substitute this expression for $R_A$ into the second equation:

$ \left( R_B + \frac{1}{50} \right) + R_B = \frac{1}{10} $

Simplify and solve for $R_B$:

$ 2 R_B + \frac{1}{50} = \frac{1}{10} $ $ 2 R_B = \frac{1}{10} - \frac{1}{50} $

Find a common denominator (50) for the subtraction:

$ 2 R_B = \frac{5}{50} - \frac{1}{50} $ $ 2 R_B = \frac{4}{50} $ $ 2 R_B = \frac{2}{25} $ $ R_B = \frac{1}{25} $

Calculate Baban's Time

Baban's rate of work is $\frac{1}{25}$ of the work per day. The time taken by Baban alone is the reciprocal of his rate:

$ \text{Time for Baban} = \frac{1}{R_B} = \frac{1}{1/25} = 25 \text{ days} $
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Important Questions from Time and Work

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  4. Each one of five men independently can complete a work in 20 days. The work is started by one person. Next day one more person joins and every next day one more person joins. From the fifth day, five persons continued working as a team. In how many days, will the work be completed?

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