This problem involves calculating the time taken by an individual (Baban) to complete a work, given information about the combined work rates of multiple people.
Let the rates of work for Athar, Baban, and Chetan be $R_A$, $R_B$, and $R_C$ respectively. The rate signifies the fraction of the work completed per day.
We have a system of three equations. Substitute the value of $R_C$ from the third equation into the first equation:
$ R_A = R_B + \frac{1}{50} $Now substitute this expression for $R_A$ into the second equation:
$ \left( R_B + \frac{1}{50} \right) + R_B = \frac{1}{10} $Simplify and solve for $R_B$:
$ 2 R_B + \frac{1}{50} = \frac{1}{10} $ $ 2 R_B = \frac{1}{10} - \frac{1}{50} $Find a common denominator (50) for the subtraction:
$ 2 R_B = \frac{5}{50} - \frac{1}{50} $ $ 2 R_B = \frac{4}{50} $ $ 2 R_B = \frac{2}{25} $ $ R_B = \frac{1}{25} $Baban's rate of work is $\frac{1}{25}$ of the work per day. The time taken by Baban alone is the reciprocal of his rate:
$ \text{Time for Baban} = \frac{1}{R_B} = \frac{1}{1/25} = 25 \text{ days} $A and B can complete a task together in 12 days, while B and C can finish it in 16 days. After A works on it for 5 days and B for 7 days, C takes the remaining 13 days to finish the work. How many days would it take for C to complete the work alone?
A is three times more efficient as a worker than B, which allows A to complete a job in 60 days less than B. If they work together, they can finish the job in:
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