A and B complete a piece of work in 24 days. If A alone can complete it in 60 days, then in how many days can B alone complete one-fourth of the same work?
10
Combined one-day work of A and B: \(\dfrac{1}{24}\).
A's one-day work: \(\dfrac{1}{60}\).
B's one-day work: \(\dfrac{1}{24} - \dfrac{1}{60} = \dfrac{5 - 2}{120} = \dfrac{3}{120} = \dfrac{1}{40}\).
So B alone can finish the whole work in 40 days.
Time B needs for one-fourth of the work: \(\dfrac{40}{4} = 10\) days.
Hence, B alone completes one-fourth of the work in 10 days.
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