This problem involves calculating the total time required for three individuals, X, Y, and Z, to complete a piece of work when working together, given their individual times.
First, determine the rate at which each person works. The rate is the amount of work done per day, which is the reciprocal of the time taken to complete the entire work.
When working together, their rates add up. To find the combined rate, we sum their individual rates:
Combined Rate = X's rate + Y's rate + Z's rate
Combined Rate = $\frac{1}{153} + \frac{1}{255} + \frac{1}{340}$
To add these fractions, find the Least Common Multiple (LCM) of the denominators (153, 255, 340).
Convert fractions to the common denominator:
Add the converted fractions:
Combined Rate = $\frac{20}{3060} + \frac{12}{3060} + \frac{9}{3060} = \frac{20 + 12 + 9}{3060} = \frac{41}{3060}$ of the work per day.
The total time required to complete the work together is the reciprocal of the combined rate.
Time Together = $\frac{1}{\text{Combined Rate}} = \frac{1}{\frac{41}{3060}} = \frac{3060}{41}$ days.
Convert the improper fraction $\frac{3060}{41}$ into a mixed number:
Divide 3060 by 41:
$3060 \div 41 = 74$ with a remainder of $26$.
So, the time taken is $74 \frac{26}{41}$ days.