A and B can do a work together in 18 days. A is three times as efficient as B. In how many days can B alone complete the work?
72 days
This problem involves the concept of time and work, specifically focusing on the relationship between efficiency and the time taken to complete a task. We are given the combined time taken by two individuals, A and B, to complete a work, and a relationship between their efficiencies. We need to find the time taken by one individual, B, to complete the same work alone.
We are given two main pieces of information:
Let the efficiency of B be represented by $E_B$.
According to the problem, A is three times as efficient as B. So, the efficiency of A ($E_A$) is:
We can assume a unit of efficiency for B for simplicity. Let $E_B = 1$ unit of work per day.
Then, $E_A = 3 \times 1 = 3$ units of work per day.
When A and B work together, their efficiencies add up. The combined efficiency ($E_{A+B}$) is:
So, A and B together complete 4 units of work each day.
We know that Work = Efficiency × Time. A and B together complete the work in 18 days with a combined efficiency of 4 units/day.
The total work (W) is:
The total amount of work to be done is 72 units.
To find the time taken by B alone to complete the work, we use the formula:
The total work is 72 units, and B's efficiency ($E_B$) is 1 unit/day.
Therefore, B alone can complete the work in 72 days.
Let's check the result:
This matches the information given in the question, confirming our calculation is correct.
| Individual/Group | Efficiency (units/day) | Time Taken (days) | Total Work (units) |
|---|---|---|---|
| B | 1 | 72 | $1 \times 72 = 72$ |
| A | 3 | 24 | $3 \times 24 = 72$ |
| A and B together | $1 + 3 = 4$ | 18 | $4 \times 18 = 72$ |
| Concept | Formula | Explanation |
|---|---|---|
| Work Done | Work = Efficiency × Time | Total work completed is the product of the rate of work (efficiency) and the time spent. |
| Efficiency | Efficiency = $\frac{\text{Work}}{\text{Time}}$ | Efficiency is the amount of work done per unit of time. |
| Time Taken | Time = $\frac{\text{Work}}{\text{Efficiency}}$ | The time needed to complete a task is the total work divided by the efficiency. |
| Combined Efficiency (A and B) | $E_{A+B} = E_A + E_B$ | When multiple people work together, their efficiencies are added. |
| Individual Time from Combined (for 2 people A & B) | If A takes 'a' days and B takes 'b' days, then time together = $\frac{ab}{a+b}$ | Useful for relating individual times to combined time. |
Time and work problems are common in quantitative aptitude. Understanding the inverse relationship between efficiency and time is crucial. If a person is more efficient, they take less time to complete the same amount of work. Conversely, if someone is less efficient, they take more time.
This problem used the efficiency approach. Another common approach involves calculating the fraction of work done per day. If B takes 'x' days, B does 1/x of the work per day. If A takes 'y' days, A does 1/y per day. Since A is 3 times as efficient as B, A takes 1/3 the time B takes, so $y = x/3$. Together they do $1/x + 1/(x/3) = 1/x + 3/x = 4/x$ of the work per day. Since they finish in 18 days, they do 1/18 of the work per day. Thus, $4/x = 1/18$, which gives $x = 4 \times 18 = 72$ days. Both methods yield the same correct answer.
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