X can finish a job in 20 days. Y can complete the same job in 15 days. If X and Y work together for 5 days and X leaves, how long will Y take to finish the remaining work?
6.25 days
Combined rate of X and Y: \(\tfrac{1}{20}+\tfrac{1}{15} = \tfrac{3+4}{60} = \tfrac{7}{60}\) per day.
Work done in 5 days: \(5\times\tfrac{7}{60} = \tfrac{35}{60} = \tfrac{7}{12}\).
Remaining work: \(1-\tfrac{7}{12} = \tfrac{5}{12}\).
Time for Y alone: \(\dfrac{5/12}{1/15} = \dfrac{5}{12}\times15 = 6.25\) days.
Hence, Y will take 6.25 days to finish the remaining work.
Mohan can do a piece of work in 10 days and Sohan in 15 days. They started working together, but after 3 days Mohan left the work . What time will Sohan take to finish the work?
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