$\frac{3}{9}, \frac{8}{14}, \frac{5}{8}, \frac{4}{9}$
To find the smallest fraction among $\frac{3}{9}, \frac{8}{14}, \frac{5}{8}, \frac{4}{9}$, we convert each fraction to its decimal equivalent and compare these values.
Calculate the decimal value for each fraction:
Arrange the decimal values in ascending order:
$0.333 \lt 0.444 \lt 0.571 \lt 0.625$
The smallest decimal value is $0.333$.
The fraction that corresponds to the smallest decimal value ($0.333$) is $\frac{3}{9}$. Therefore, $\frac{3}{9}$ is the smallest fraction.
Which fraction among the following is the least ?
\(\frac{5}{11}, \frac{7}{12}, \frac{8}{13}, \frac{9}{17}\)
Find the value of the following expression:
\(\frac{{3 \div 1 \times 2 + 5 - 2}}{{3 \times 3 - 2}}\)
Simplify the expression 441 ÷ \(\left[270 \div \frac{3}{7}+\left(17\div \frac{1}{3}\right)-\left(8\frac{1}{2}-\frac{5}{2}\right)\right]\)
If the sum of two positive numbers is 65 and the square root of their product is 26, then the sum of their reciprocals is:
The value of \(9 \div [\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{6}\div(\frac{3}{4}-\frac{1}{3})\;of\;\frac{2}{9}]\) is: