The question asks for a number that, when added to $\frac{1}{2}$, results in $2$. We need to find the value $x$ in the equation:
$ \frac{1}{2} + x = 2 $
To find $x$, we subtract $\frac{1}{2}$ from both sides of the equation:
$ x = 2 - \frac{1}{2} $
To subtract the fractions, we find a common denominator, which is $2$. We rewrite $2$ as $\frac{4}{2}$:
$ x = \frac{4}{2} - \frac{1}{2} $
Subtract the numerators:
$ x = \frac{4 - 1}{2} $
$ x = \frac{3}{2} $
The value that needs to be added to $\frac{1}{2}$ to get $2$ is $\frac{3}{2}$. This corresponds to Option A.
What is the value of
$\frac{7}{9} - \frac{11}{12} + \frac{13}{16} - \frac{1}{8}$?
5 \(\frac{3}{4}\) + x + 2 \(\frac{1}{2}\) = 10 \(\frac{1}{8}\) Find the value of x.
Simplify the expression 441 ÷ \(\left[270 \div \frac{3}{7}+\left(17\div \frac{1}{3}\right)-\left(8\frac{1}{2}-\frac{5}{2}\right)\right]\)
Number 0.232323 can be written in rational form as:
Solve: \(\frac{1}{2}\) [{-2(2 + 3)*20}/2]
Match the following.
Column I | Column II | ||
a. | Equivalent fraction of \(\frac{7}{12}\) is | i. | Proper fraction |
b. | Equivalent fraction of \(\frac{9}{15}\) is | ii. | Improper fraction |
c. | \(\frac{7}{11}\) is | iii. | \(\frac{21}{36}\) |
d. | \(\frac{19}{5}\) is | iv. | \(\frac{3}{5}\) |