Let the unknown number be represented by '$x$'.
The problem states that "Two-fifth of seven-seventeenth of three-fifth of a number is 84". This translates to the following equation:
$ \frac{2}{5} \times \frac{7}{17} \times \frac{3}{5} \times x = 84 $
Multiply the given fractions together:
$ \frac{2 \times 7 \times 3}{5 \times 17 \times 5} = \frac{42}{425} $
The equation simplifies to:
$ \frac{42}{425} \times x = 84 $
To isolate '$x$', rearrange the equation:
$ x = 84 \times \frac{425}{42} $
Perform the calculation:
$ x = 2 \times 425 $
$ x = 850 $
The value of the number is 850.
The final step is to find 40% of the number '$x$' (which is 850).
Convert 40% to a decimal or fraction: $40\% = \frac{40}{100} = 0.4$.
Calculate 40% of 850:
$ 0.4 \times 850 $
Alternatively, using fractions:
$ \frac{40}{100} \times 850 = \frac{2}{5} \times 850 $
$ = \frac{2 \times 850}{5} = 2 \times 170 $
$ = 340 $
Thus, 40% of the number is 340.
Which fraction among the following is the least ?
\(\frac{5}{11}, \frac{7}{12}, \frac{8}{13}, \frac{9}{17}\)
Find the value of the following expression:
\(\frac{{3 \div 1 \times 2 + 5 - 2}}{{3 \times 3 - 2}}\)
Simplify the expression 441 ÷ \(\left[270 \div \frac{3}{7}+\left(17\div \frac{1}{3}\right)-\left(8\frac{1}{2}-\frac{5}{2}\right)\right]\)
If the sum of two positive numbers is 65 and the square root of their product is 26, then the sum of their reciprocals is:
The value of \(9 \div [\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{6}\div(\frac{3}{4}-\frac{1}{3})\;of\;\frac{2}{9}]\) is: