Let the original fraction be represented algebraically as $\frac{x}{y}$.
The numerator $x$ is increased by 30%. The new numerator is calculated as:
$ x + (30\% \times x) = x + (0.30 \times x) = 1.30x $
The denominator $y$ is decreased by 35%. The new denominator is calculated as:
$ y - (35\% \times y) = y - (0.35 \times y) = 0.65y $
The resulting fraction after these modifications is $\frac{1.30x}{0.65y}$.
We are given that this new fraction equals $\frac{3}{15}$, which simplifies to $\frac{1}{5}$.
$ \frac{1.30x}{0.65y} = \frac{1}{5} $
First, simplify the numerical coefficients in the equation:
$ \frac{1.30}{0.65} = \frac{130}{65} = 2 $
Substitute this back into the equation:
$ 2 \times \frac{x}{y} = \frac{1}{5} $
To find the original fraction $\frac{x}{y}$, divide both sides by 2:
$ \frac{x}{y} = \frac{1}{5 \times 2} $
$ \frac{x}{y} = \frac{1}{10} $
Thus, the original fraction is $\frac{1}{10}$.
What is the value of
$\frac{7}{9} - \frac{11}{12} + \frac{13}{16} - \frac{1}{8}$?
5 \(\frac{3}{4}\) + x + 2 \(\frac{1}{2}\) = 10 \(\frac{1}{8}\) Find the value of x.
Simplify the expression 441 ÷ \(\left[270 \div \frac{3}{7}+\left(17\div \frac{1}{3}\right)-\left(8\frac{1}{2}-\frac{5}{2}\right)\right]\)
Number 0.232323 can be written in rational form as:
Solve: \(\frac{1}{2}\) [{-2(2 + 3)*20}/2]
Match the following.
Column I | Column II | ||
a. | Equivalent fraction of \(\frac{7}{12}\) is | i. | Proper fraction |
b. | Equivalent fraction of \(\frac{9}{15}\) is | ii. | Improper fraction |
c. | \(\frac{7}{11}\) is | iii. | \(\frac{21}{36}\) |
d. | \(\frac{19}{5}\) is | iv. | \(\frac{3}{5}\) |