First, identify the whole number parts and the fractional parts of the given expression:
Expression: $3\frac{2}{3} + 6\frac{7}{12} + 4\frac{9}{36} + 5 + 7\frac{1}{12}$
Sum of Whole Numbers:
$3 + 6 + 4 + 5 + 7 = 25$
Sum of Fractions:
Simplify $\frac{9}{36}$ to $\frac{1}{4}$.
Sum = $\frac{2}{3} + \frac{7}{12} + \frac{1}{4} + \frac{1}{12}$
Find the Least Common Multiple (LCM) of the denominators (3, 12, 4), which is 12.
Convert fractions to have a denominator of 12:
Add the fractions: $\frac{8}{12} + \frac{7}{12} + \frac{3}{12} + \frac{1}{12} = \frac{8 + 7 + 3 + 1}{12} = \frac{19}{12}$
Total Sum = Sum of Whole Numbers + Sum of Fractions
Total Sum = $25 + \frac{19}{12}$
Convert the improper fraction $\frac{19}{12}$ to a mixed number:
$\frac{19}{12} = 1\frac{7}{12}$
Total Sum = $25 + 1\frac{7}{12} = 26\frac{7}{12}$
The current sum is $26\frac{7}{12}$. To make this sum a whole number, we need to add a fraction that completes the current fractional part ($\frac{7}{12}$) to the next whole number (1).
Fraction needed = $1 - \frac{7}{12}$
Fraction needed = $\frac{12}{12} - \frac{7}{12} = \frac{5}{12}$
The smallest fraction that should be added is $\frac{5}{12}$.
Which fraction among the following is the least ?
\(\frac{5}{11}, \frac{7}{12}, \frac{8}{13}, \frac{9}{17}\)
Find the value of the following expression:
\(\frac{{3 \div 1 \times 2 + 5 - 2}}{{3 \times 3 - 2}}\)
Simplify the expression 441 ÷ \(\left[270 \div \frac{3}{7}+\left(17\div \frac{1}{3}\right)-\left(8\frac{1}{2}-\frac{5}{2}\right)\right]\)
If the sum of two positive numbers is 65 and the square root of their product is 26, then the sum of their reciprocals is:
The value of \(9 \div [\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{6}\div(\frac{3}{4}-\frac{1}{3})\;of\;\frac{2}{9}]\) is: