can be written in the form of:
The question asks to convert the repeating decimal $1.236576576...$ into a fraction. The repeating block is '576'.
Let the number be x. So, $x = 1.236576576...$
Identify the non-repeating part ('23') and the repeating part ('576'). There are 2 digits before the repeating block and 3 digits in the repeating block.
Multiply x by $10^2 = 100$ to move the decimal point just before the repeating block:
$100x = 123.6576576...$ (Equation 1)
Multiply x by $10^{(2+3)} = 10^5 = 100000$ to move the decimal point to the end of the first repeating block:
$100000x = 123657.6576576...$ (Equation 2)
Subtract Equation 1 from Equation 2 to eliminate the repeating decimal part:
$100000x - 100x = 123657.6576576... - 123.6576576...$
$99900x = 123657 - 123$
$99900x = 123534$
Solve for x:
$x = \frac{123534}{99900}$
This result matches option 3.
Which fraction among the following is the least ?
\(\frac{5}{11}, \frac{7}{12}, \frac{8}{13}, \frac{9}{17}\)
Find the value of the following expression:
\(\frac{{3 \div 1 \times 2 + 5 - 2}}{{3 \times 3 - 2}}\)
Simplify the expression 441 ÷ \(\left[270 \div \frac{3}{7}+\left(17\div \frac{1}{3}\right)-\left(8\frac{1}{2}-\frac{5}{2}\right)\right]\)
If the sum of two positive numbers is 65 and the square root of their product is 26, then the sum of their reciprocals is:
The value of \(9 \div [\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{6}\div(\frac{3}{4}-\frac{1}{3})\;of\;\frac{2}{9}]\) is: