We need to find a fraction based on two conditions.
Let the fraction be represented as $\frac{x}{y}$, where $x$ is the numerator and $y$ is the denominator.
We can solve this system of equations. First, express $y$ from the first equation:
$y = 11 - x$Now, substitute this expression for $y$ into the second equation:
$\frac{x-1}{11-x} = \frac{1}{4}$Cross-multiply to solve for $x$:
$4(x-1) = 1(11-x)$ $4x - 4 = 11 - x$Combine like terms:
$4x + x = 11 + 4$ $5x = 15$ $x = \frac{15}{5}$ $x = 3$Now, find the value of $y$ using $y = 11 - x$:
$y = 11 - 3$ $y = 8$The numerator ($x$) is 3 and the denominator ($y$) is 8. Therefore, the fraction is:
$\frac{3}{8}$Both conditions are satisfied.
What is the value of
$\frac{7}{9} - \frac{11}{12} + \frac{13}{16} - \frac{1}{8}$?
5 \(\frac{3}{4}\) + x + 2 \(\frac{1}{2}\) = 10 \(\frac{1}{8}\) Find the value of x.
Simplify the expression 441 ÷ \(\left[270 \div \frac{3}{7}+\left(17\div \frac{1}{3}\right)-\left(8\frac{1}{2}-\frac{5}{2}\right)\right]\)
Number 0.232323 can be written in rational form as:
Solve: \(\frac{1}{2}\) [{-2(2 + 3)*20}/2]
Match the following.
Column I | Column II | ||
a. | Equivalent fraction of \(\frac{7}{12}\) is | i. | Proper fraction |
b. | Equivalent fraction of \(\frac{9}{15}\) is | ii. | Improper fraction |
c. | \(\frac{7}{11}\) is | iii. | \(\frac{21}{36}\) |
d. | \(\frac{19}{5}\) is | iv. | \(\frac{3}{5}\) |