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Question

The value of $\frac{4}{3} + \left( \frac{1}{1 + \frac{5}{6}} \right) - \frac{5}{4}$ is

This question was previously asked in
RRB NTPC 2024 CBT 1 Question Paper (28-Aug-2025) (Shift 3)
The correct answer is
$\frac{83}{132}$

To solve the expression \(\frac{4}{3} + \left( \frac{1}{1 + \frac{5}{6}} \right) - \frac{5}{4}\), we will evaluate each part step-by-step.

  1. First, simplify the inner expression \(\frac{1}{1 + \frac{5}{6}}\):
    • The expression inside the parentheses is \(1 + \frac{5}{6}\).
    • Convert \(1\) to a fraction with the same denominator as \(\frac{5}{6}\), which is \(\frac{6}{6}\).
    • Now, add the fractions: \(\frac{6}{6} + \frac{5}{6} = \frac{11}{6}\).
    • Now, we take the reciprocal of \(\frac{11}{6}\), which gives us \(\frac{6}{11}\).
  2. Substitute \(\frac{6}{11}\) back into the original expression, so it becomes \(\frac{4}{3} + \frac{6}{11} - \frac{5}{4}\).
  3. Find a common denominator to add and subtract these fractions. The denominators are \(3\), \(11\), and \(4\).
    • The least common multiple (LCM) of \(3\), \(11\), and \(4\) is \(132\).
  4. Convert each fraction to have a denominator of \(132\):
    • Convert \(\frac{4}{3}\): \(\frac{4}{3} = \frac{4 \times 44}{3 \times 44} = \frac{176}{132}\).
    • Convert \(\frac{6}{11}\): \(\frac{6}{11} = \frac{6 \times 12}{11 \times 12} = \frac{72}{132}\).
    • Convert \(\frac{5}{4}\): \(\frac{5}{4} = \frac{5 \times 33}{4 \times 33} = \frac{165}{132}\).
  5. Combine the fractions:
    • Add and subtract the numerators: \(176 + 72 - 165 = 83\).
    • Place the result over the common denominator: \(\frac{83}{132}\).

Thus, the value of the expression is \(\frac{83}{132}\), which matches the given correct option.

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Similar Questions

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Important Questions from Fractions

  1. Which fraction among the following is the least ?

    \(\frac{5}{11}, \frac{7}{12}, \frac{8}{13}, \frac{9}{17}\)

  2. Find the value of the following expression:

    \(\frac{{3 \div 1 \times 2 + 5 - 2}}{{3 \times 3 - 2}}\)

  3. Simplify the expression 441 ÷  \(\left[270 \div \frac{3}{7}+\left(17\div \frac{1}{3}\right)-\left(8\frac{1}{2}-\frac{5}{2}\right)\right]\)

  4. If the sum of two positive numbers is 65 and the square root of their product is 26, then the sum of their reciprocals is:

  5. The value of \(9 \div [\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{6}\div(\frac{3}{4}-\frac{1}{3})\;of\;\frac{2}{9}]\)  is:

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