The problem asks us to find the reciprocal of the sum of the reciprocals of two given fractions: $\frac{5}{7}$ and $\frac{9}{5}$. We can solve this step-by-step:
Next, we add the reciprocals found in Step 1:
Sum = $\frac{7}{5} + \frac{5}{9}$
To add these fractions, we find a common denominator, which is $5 \times 9 = 45$.
Sum = $\frac{7 \times 9}{5 \times 9} + \frac{5 \times 5}{9 \times 5}$
Sum = $\frac{63}{45} + \frac{25}{45}$
Sum = $\frac{63 + 25}{45}$
Sum = $\frac{88}{45}$
Finally, we find the reciprocal of the sum calculated in Step 2.
The sum is $\frac{88}{45}$.
The reciprocal of the sum is $\frac{45}{88}$.
The reciprocal of the sum of the reciprocals of $\frac{5}{7}$ and $\frac{9}{5}$ is $\frac{45}{88}$.
What is the value of
$\frac{7}{9} - \frac{11}{12} + \frac{13}{16} - \frac{1}{8}$?
5 \(\frac{3}{4}\) + x + 2 \(\frac{1}{2}\) = 10 \(\frac{1}{8}\) Find the value of x.
Simplify the expression 441 ÷ \(\left[270 \div \frac{3}{7}+\left(17\div \frac{1}{3}\right)-\left(8\frac{1}{2}-\frac{5}{2}\right)\right]\)
Number 0.232323 can be written in rational form as:
Solve: \(\frac{1}{2}\) [{-2(2 + 3)*20}/2]
Match the following.
Column I | Column II | ||
a. | Equivalent fraction of \(\frac{7}{12}\) is | i. | Proper fraction |
b. | Equivalent fraction of \(\frac{9}{15}\) is | ii. | Improper fraction |
c. | \(\frac{7}{11}\) is | iii. | \(\frac{21}{36}\) |
d. | \(\frac{19}{5}\) is | iv. | \(\frac{3}{5}\) |