Question
The present age of a man is 4 years more than twice the present age of his son. After 6 years, the sum of their ages will be 58 years. What is the present age of the son?
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RRB NTPC 2025 Under Graduate CBT 1 Question Paper PDF (20-Jun-2026) (Shift 3)
The correct answer is
14 years
Let the son's present age be \(s\) years.
The man's present age is 4 more than twice the son's age: \(2s + 4\) years.
After 6 years, the son is \(s + 6\) and the man is \(2s + 4 + 6 = 2s + 10\).
Their sum after 6 years is 58: \((s + 6) + (2s + 10) = 58\).
Simplify: \(3s + 16 = 58\), so \(3s = 42\).
Therefore \(s = 14\).
Hence, the present age of the son is 14 years.
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