The present age of a man is 4 years more than twice the present age of his son. After 6 years, the sum of their ages will be 58 years. What is the present age of the son?
14 years
Let the son's present age be \(s\) years.
The man's present age is 4 more than twice the son's age: \(2s + 4\) years.
After 6 years, the son is \(s + 6\) and the man is \(2s + 4 + 6 = 2s + 10\).
Their sum after 6 years is 58: \((s + 6) + (2s + 10) = 58\).
Simplify: \(3s + 16 = 58\), so \(3s = 42\).
Therefore \(s = 14\).
Hence, the present age of the son is 14 years.
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