Let $M$ represent the mother's present age and $D$ represent the daughter's present age.
The problem provides two conditions relating their ages:
$3M = 9D + 24$
$4D = M - 2$
First, simplify the first equation by dividing both sides by 3:
$M = 3D + 8 \quad (1)$
Next, rearrange the second equation to express $M$ in terms of $D$:
$M = 4D + 2 \quad (2)$
Now, set the two expressions for $M$ equal to each other to solve for $D$:
$3D + 8 = 4D + 2$
Subtract $3D$ from both sides:
$8 = D + 2$
Subtract 2 from both sides:
$D = 6$
The daughter's present age is 6 years.
Substitute the value of $D$ (6) back into either equation (1) or (2). Using equation (2):
$M = 4(6) + 2$
$M = 24 + 2$
$M = 26$
The mother's present age is 26 years.
The question asks for the difference between the mother's and daughter's ages:
$Difference = M - D$
$Difference = 26 - 6$
$Difference = 20$
The difference between the mother's and daughter's ages is 20 years.
The age of Dr. Pandey is four times the age of his son. After 10 years, the age of Dr. Pandey will be twice the age of his son. The present age of Dr. Pandey's son is?
Three years ago, the average age of a family of six members was 19 years. Since then, a boy has been born, and the average age of the family is the same today as it was three years ago. What is the age of the boy?
Amita is 2 years older than her friend Amrita. Amita's father is twice as old as Amita, and Amrita is twice as old as her sister. The ages of Amita's father and Amrita's sister differ by 43 years. The sum of the ages (in years) of Amita and Amrita is: