Let the present ages of A and B be $5x$ and $3x$ respectively, according to the given ratio $5:3$.
After 5 years, their ages will be $(5x + 5)$ and $(3x + 5)$.
The problem states that the ratio of their ages after 5 years will be $10:7$. Therefore, we can set up the equation:
$ \frac{5x + 5}{3x + 5} = \frac{10}{7} $Cross-multiply to solve the equation:
$7(5x + 5) = 10(3x + 5)$
$35x + 35 = 30x + 50$
$35x - 30x = 50 - 35$
$5x = 15$
$x = \frac{15}{5}$
$x = 3$
Now, find the present ages:
The difference between their present ages is:
Difference = A's age - B's age = $15 - 9 = 6$ years.
Three years ago, the average age of a family of six members was 19 years. Since then, a boy has been born, and the average age of the family is the same today as it was three years ago. What is the age of the boy?
Amita is 2 years older than her friend Amrita. Amita's father is twice as old as Amita, and Amrita is twice as old as her sister. The ages of Amita's father and Amrita's sister differ by 43 years. The sum of the ages (in years) of Amita and Amrita is: