Let D be the daughter's current age.
We know that 3 years ago, her age was 4.
This gives us the equation:
$D - 3 = 4$
Solving for D:
$D = 4 + 3 = 7$
So, the daughter is currently 7 years old.
Let W be the wife's current age.
The wife's age is 5 times the daughter's age.
Using the daughter's age, D = 7:
$W = 5 \times D$
$W = 5 \times 7 = 35$
The wife is currently 35 years old.
Let R be Ravi's current age.
Ravi is 5 years older than his wife.
Using the wife's age, W = 35:
$R = W + 5$
$R = 35 + 5 = 40$
Therefore, Ravi's present age is 40 years.
Three years ago, the average age of a family of six members was 19 years. Since then, a boy has been born, and the average age of the family is the same today as it was three years ago. What is the age of the boy?
Amita is 2 years older than her friend Amrita. Amita's father is twice as old as Amita, and Amrita is twice as old as her sister. The ages of Amita's father and Amrita's sister differ by 43 years. The sum of the ages (in years) of Amita and Amrita is: