This problem involves finding the current age of the daughter based on two conditions relating her age to her mother's age at different times.
Let $D$ represent the daughter's current age and $M$ represent the mother's current age.
We can solve this system of two equations. Substitute the first equation ($M = 3D$) into the second equation:
The daughter's current age is 15 years.
Let's check the conditions:
Therefore, the daughter's current age is 15 years.
The age of Dr. Pandey is four times the age of his son. After 10 years, the age of Dr. Pandey will be twice the age of his son. The present age of Dr. Pandey's son is?
Three years ago, the average age of a family of six members was 19 years. Since then, a boy has been born, and the average age of the family is the same today as it was three years ago. What is the age of the boy?
Amita is 2 years older than her friend Amrita. Amita's father is twice as old as Amita, and Amrita is twice as old as her sister. The ages of Amita's father and Amrita's sister differ by 43 years. The sum of the ages (in years) of Amita and Amrita is: