Amita is 2 years older than her friend Amrita. Amita's father is twice as old as Amita, and Amrita is twice as old as her sister. The ages of Amita's father and Amrita's sister differ by 43 years. The sum of the ages (in years) of Amita and Amrita is:
54
The correct answer is Option 1 i.e. 54.
Let, Amita's age = x so,
Amrits's age = x - 2
Amita's father age = 2x,
Amrita's sister age = (x - 2)/2
According to the question
⇒ 2x - (x - 2)/2 = 43
⇒ 4x - x + 2 = 86
⇒ 3x + 2 = 86
⇒ 3x = 84
⇒ x = 28
Amita age = x = 28 years
Amrita's age = x - 2 = 26 years
Sum = 28 + 26 = 54 years
Similar Questions
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Important Questions from Problems on Age
Three years ago, the average age of a family of six members was 19 years. Since then, a boy has been born, and the average age of the family is the same today as it was three years ago. What is the age of the boy?
- A mother is now three times as old as her daughter. 5 years ago, she was four times as old as her daughter. What is the current age of the daughter?
- If 3 times a mother's present age is 24 years more than 9 times her daughter's present age, and 4 times the daughter's present age is 2 years less than the mother's present age, then what is the difference (in years) between the ages of the mother and the daughter?
- John is twice as old as Jean. After 3 years, the sum of their ages will be 66 years. What are the present ages of Jean and John, respectively?
- The ages of A and B are in the ratio of 5 : 3. After 5 years the ratio of their ages will be 10 : 7. What is the difference between present ages of A and B(in years)?
