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Question

Age of A is 3 times more than that of B and half as that of C. If the sum of their ages is 120 years, what is the age (in years) of A?

This question was previously asked in
RRB NTPC 2019 CBT 1 Question Paper PDF (31-Jan-2021) (Shift 1)
The correct answer is
36

Age Calculation Steps

Let the age of B be represented by '$x$' years.

According to the question:

  • Age of A is 3 times B's age: Age(A) = $3x$ years.
  • Age of A is half the age of C: Age(A) = $\frac{\text{Age(C)}}{2}$, which implies Age(C) = $2 \times$ Age(A).
  • Substituting Age(A) = $3x$, we get Age(C) = $2 \times (3x) = 6x$ years.

Sum of Ages Equation

The sum of the ages of A, B, and C is given as 120 years.

Age(A) + Age(B) + Age(C) = 120

Substituting the expressions in terms of $x$:

$3x + x + 6x = 120$

Solving for Age of A

Combine the terms involving $x$:

$10x = 120$

Solve for $x$:

$x = \frac{120}{10}$

$x = 12$

Now, calculate the age of A using the value of $x$:

Age(A) = $3x = 3 \times 12 = 36$ years.

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Similar Questions

  1. A mother is now three times as old as her daughter. 5 years ago, she was four times as old as her daughter. What is the current age of the daughter?
  2. John is twice as old as Jean. After 3 years, the sum of their ages will be 66 years. What are the present ages of Jean and John, respectively?
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Important Questions from Problems on Age

  1. A mother is now three times as old as her daughter. 5 years ago, she was four times as old as her daughter. What is the current age of the daughter?
  2. John is twice as old as Jean. After 3 years, the sum of their ages will be 66 years. What are the present ages of Jean and John, respectively?
  3. The ages of A and B are in the ratio of 5 : 3. After 5 years the ratio of their ages will be 10 : 7. What is the difference between present ages of A and B(in years)?
  4. The sum of the reciprocals of the ages of two colleagues is nine times the difference of the reciprocals of their ages. If the ratio of the products of their ages to the sum of their ages is 100 : 9, Find their ages.
  5. The ages of two persons differ by 15 years. If 5 years ago, the age of the older person was twice that of the younger one, then their present ages (in years) are:
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