Metamers are a specific type of structural isomerism. Molecules are classified as metamers if they possess the same molecular formula and the same functional group, but differ in the structure of the alkyl or aryl groups attached to the functional group. This typically occurs with functional groups like ethers (-O-), thioethers (-S-), secondary amines (-NH-), ketones (-CO-), and esters (-COO-).
Let's examine the given pairs to identify the metamers:
Both molecules share the same molecular formula ($C_4H_{10}O$) and the same functional group (ether). They differ solely in the arrangement of alkyl groups around the oxygen atom. Therefore, $CH_3OCH_2CH_2CH_3$ and $CH_3CH_2OCH_2CH_3$ are metamers.
The pair of molecules that exhibits metamerism among the choices is $CH_3OCH_2CH_2CH_3$ and $CH_3CH_2OCH_2CH_3$, as they are both ethers ($C_4H_{10}O$) with different alkyl group combinations around the oxygen atom.
Select the reagents that reduce nitriles to primary amines :
A. (i) $LiAlH_4$ ; (ii) $H_2O$
B. $Sn + HCl$
C. $H_2 / Ni$
D. $Na(Hg) / C_2H_5OH$
E. $Br_2 / \text{aq. } NaOH$
Choose the correct answer from the options given below :
The major product Z formed in the following sequence of reactions is :
$$C_2H_6 \xrightarrow{Cl_2, \text{UV light}} X \text{ (monochlorinated product)} \xrightarrow{NH_3} Y \xrightarrow{(i) NaNO_2, HCl, (ii) H_2O} Z$$
The correct IUPAC name of the following compound is :

In the following reaction sequence, X and Z respectively are :
The number of chlorine atoms present in the organic products X and Y of the following reactions, respectively, are :
Two products X and Y are formed in the following reaction sequence.
The suitable method that can be used for the separation of products X and Y is :
| List I (Reactions) | List II (Reagents) |
A.![]() | I. (i) oleum, (ii) $NaOH, \Delta$, (iii) $H^+$ |
| B. $CH_3COOH \rightarrow CH_3CH_2OH$ | II. (i) $O_3$, (ii) $H_2O/H^+$ |
C. $CH_3CH_2CH_2OH \rightarrow $ ![]() | III. (i) $CH_3OH, H^+$, (ii) $H_2$, catalyst |
D. ![]() | IV. (i) conc. $H_2SO_4, \Delta$, (ii) $H_2O$ |
Match List I with List II.
The following two reactions give the same foul smelling product Z.
$$C_2H_5Cl \xrightarrow{X} Z$$

X and Z, respectively, are :
Given below are two statements:
Statement I: The dipole moment of R-CN is greater than R-NC and R-NC can undergo hydrolysis under acidic medium to produce 
Statement II: R-CN hydrolyses under acidic medium to produce a compound which on treatment with $\text{SOCl}_2$, followed by the addition of $\text{NH}_3$ gives another compound(x). This compound (x) on treatment with $\text{NaOCl/NaOH}$ gives a product, that on treatment with $\text{CHCl}_3\text{/KOH/}\Delta$ produces R-NC
In the light of the above statements, choose the correct answer from the options given below