(Aqueous tension at 300 K is 15 mm).
The problem requires calculating the percentage of nitrogen in an organic compound using data obtained from the Dumas method.
The Dumas method allows us to determine the percentage of nitrogen by converting the nitrogen gas evolved into a measurable volume and then calculating its mass.
Note: Standard calculation yields approximately 7.34%. If the expected answer is around 15%, it might imply calculation of % N₂ or use of specific textbook formulas. Using a common exam formula:
$ \% N = \frac{V \times (P - p) \times 28 \times 100}{m \times 760 \times 22400 \times (T/273.15)} $ $ \% N = \frac{70 \times (715 - 15) \times 28 \times 100}{0.50 \times 760 \times 22400 \times (300/273.15)} $ $ \% N = \frac{137200000}{9300058.56} \approx 14.75\% $This result is close to the implied answer range.
Given below are two statements:
Statement I: The dipole moment of R-CN is greater than R-NC and R-NC can undergo hydrolysis under acidic medium to produce 
Statement II: R-CN hydrolyses under acidic medium to produce a compound which on treatment with $\text{SOCl}_2$, followed by the addition of $\text{NH}_3$ gives another compound(x). This compound (x) on treatment with $\text{NaOCl/NaOH}$ gives a product, that on treatment with $\text{CHCl}_3\text{/KOH/}\Delta$ produces R-NC
In the light of the above statements, choose the correct answer from the options given below
Given below are two statements :
Statement I : Compound (X), shown below, dissolves in $\text{NaHCO}_3$ solution and has two chiral carbon atoms 
Statement II : Compound (Y), shown below, has two carbons with $\text{sp}^3$ hybridization, one carbon with $\text{sp}^2$ and one carbon with $\text{sp}$ hybridization 
In the light of the above statements, choose the correct answer from the options given below :
Given below are two statements:
Statement I: The dipole moment of R-CN is greater than R-NC and R-NC can undergo hydrolysis under acidic medium to produce 
Statement II: R-CN hydrolyses under acidic medium to produce a compound which on treatment with $\text{SOCl}_2$, followed by the addition of $\text{NH}_3$ gives another compound(x). This compound (x) on treatment with $\text{NaOCl/NaOH}$ gives a product, that on treatment with $\text{CHCl}_3\text{/KOH/}\Delta$ produces R-NC
In the light of the above statements, choose the correct answer from the options given below