Identifying Gas Q from Volume and Mass
The Grignard reagent $\text{RMgBr}$ reacts with water to produce an alkane $\text{RH}$ (gas Q) and $\text{Mg(OH)Br}$.
Reaction: $\text{RMgBr} + \text{H}_2\text{O} \rightarrow \text{RH} \uparrow + \text{Mg(OH)Br}$
We are given that 1 gram of gas Q occupies $1.4 \text{ dm}^3$ (or $1.4 \text{ L}$) at Standard Temperature and Pressure (STP).
At STP, the molar volume of any gas is $22.4 \text{ L/mol}$.
Using this information, we can calculate the molar mass of gas Q:
Molar Mass of Q = $ \frac{\text{Mass}}{\text{Volume}} \times \text{Molar Volume at STP} $
Molar Mass of Q = $ \frac{1 \text{ g}}{1.4 \text{ L}} \times 22.4 \text{ L/mol} = 16 \text{ g/mol} $
The alkane with a molar mass of approximately $16 \text{ g/mol}$ is methane ($\text{CH}_4$, Molar Mass = $12 + 4 \times 1 = 16 \text{ g/mol}$).
Therefore, gas Q is methane ($\text{CH}_4$), and the R group in the Grignard reagent $\text{RMgBr}$ is methyl ($\text{CH}_3$).
So, the Grignard reagent (P) is $\text{CH}_3\text{MgBr}$.
Synthesizing Compound Z using Dry Ice
The Grignard reagent $\text{CH}_3\text{MgBr}$ reacts with dry ice ($\text{CO}_2$) followed by acid hydrolysis ($\text{H}_3\text{O}^+$) to form a carboxylic acid.
Step 1: Reaction with $\text{CO}_2$
$ \text{CH}_3\text{MgBr} + \text{CO}_2 \rightarrow \text{CH}_3\text{COOMgBr} $
Step 2: Acid Hydrolysis
$ \text{CH}_3\text{COOMgBr} + \text{H}_3\text{O}^+ \rightarrow \text{CH}_3\text{COOH} + \text{Mg}^{2+} + \text{Br}^- $
The compound Z is acetic acid ($\text{CH}_3\text{COOH}$).
Calculating Weight of Compound Z
We need to find the weight of 0.1 mole of compound Z ($\text{CH}_3\text{COOH}$).
First, calculate the molar mass of $\text{CH}_3\text{COOH}$:
Molar Mass = $ (2 \times \text{Atomic Mass of C}) + (4 \times \text{Atomic Mass of H}) + (2 \times \text{Atomic Mass of O}) $
Molar Mass = $ (2 \times 12.011) + (4 \times 1.008) + (2 \times 15.999) $
Molar Mass = $ 24.022 + 4.032 + 31.998 = 60.052 \text{ g/mol} $
Now, calculate the weight of 0.1 mole of $\text{CH}_3\text{COOH}$:
Weight = Moles $ \times $ Molar Mass
Weight = $ 0.1 \text{ mol} \times 60.052 \text{ g/mol} = 6.0052 \text{ g} $
The question asks for the weight to the nearest integer.
Nearest integer to $6.0052 \text{ g}$ is $6 \text{ g}$.
Similar Questions
- In Dumas method for estimation of nitrogen, 0.50 g of an organic compound gave 70 mL of nitrogen collected at 300 K and 715 mm pressure. The percentage of nitrogen in the organic compound is ______ %.
(Aqueous tension at 300 K is 15 mm). - $0.25 \text{ g}$ of an organic compound "A" containing carbon, hydrogen and oxygen was analysed using the combustion method. There was an increase in mass of $\text{CaCl}_2$ tube and potash tube at the end of the experiment. The amount was found to be $0.15 \text{ g}$ and $0.1837 \text{ g}$, respectively. The percentage of oxygen in compound A is ______ %. (Nearest integer)
(Given: molar mass in $\text{g mol}^{-1}$ $\text{H} : 1, \text{C} : 12, \text{O} : 16$) - Consider all the structural isomers with molecular formula $\text{C}_5\text{H}_{11}\text{Br}$ are separately treated with $\text{KOH(aq)}$ to give respective substitution products, without any rearrangement. The number of products which can exhibit optical isomerism from these is ___________.
Consider the following reactions sequence
When the product (P) is subjected to Carius analysis using $\text{AgNO}_3$, $1.0\text{ g}$ of the product (P) will produce __________ g of the precipitate of AgBr. (Nearest Integer)
(Given : molar mass in $\text{g mol}^{-1}$ C : 12, H : 1, O : 16, N : 14, Br : 80, Ag : 108)Consider the following sequence of reactions to give the major product (X)
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$\text{P} = \_\_\_\_\_\_\_\_~\text{g}$.
(Given molar mass in $\text{g~mol}^{-1}$ $\text{H}: 1, \text{C}: 12, \text{O}: 16, \text{Cl}: 35.5$)- 2.0 g of a bromo hydrocarbon (X) was subjected to Carius analysis, gave 3.36 g of AgBr. The percentage of carbon in the compound (X) is 26.7%. Total number of carbon atoms in the empirical formula for compound (X) is _______.
(Given molar mass in $\text{g~mol}^{-1}$ $\text{H}: 1, \text{C}: 12, \text{Br} : 80, \text{Ag} : 108$) - The number of isomeric compounds (structural isomers only) possible with the molecular formula $C_5H_{10}O_2$, which do not react with metallic sodium is ________
Among the following, how many hydrocarbon (s) with formula $C_{10}H_{16}$ which on reaction with acidic potassium permagenate yield(s) same product? ____________
On treatment of the following compound with a strong acid, the most susceptible site for bond cleavage is :-
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Important Questions from Organic Chemistry
- In Dumas method for estimation of nitrogen, 0.50 g of an organic compound gave 70 mL of nitrogen collected at 300 K and 715 mm pressure. The percentage of nitrogen in the organic compound is ______ %.
(Aqueous tension at 300 K is 15 mm). - $0.25 \text{ g}$ of an organic compound "A" containing carbon, hydrogen and oxygen was analysed using the combustion method. There was an increase in mass of $\text{CaCl}_2$ tube and potash tube at the end of the experiment. The amount was found to be $0.15 \text{ g}$ and $0.1837 \text{ g}$, respectively. The percentage of oxygen in compound A is ______ %. (Nearest integer)
(Given: molar mass in $\text{g mol}^{-1}$ $\text{H} : 1, \text{C} : 12, \text{O} : 16$) - Consider all the structural isomers with molecular formula $\text{C}_5\text{H}_{11}\text{Br}$ are separately treated with $\text{KOH(aq)}$ to give respective substitution products, without any rearrangement. The number of products which can exhibit optical isomerism from these is ___________.
The major products U and V in the following reaction are
In the following sequence of reactions, what is the end product 'Z'?
