We need to find the number of electrons (X) involved when iodide ion ($\text{I}^-$) is oxidized to iodine ($\text{I}_2$) by acidified $\text{K}_2\text{Cr}_2\text{O}_7$.
The oxidation half-reaction is: $2\text{I}^- \rightarrow \text{I}_2 + 2e^-$
However, the question asks for electrons involved *during the oxidation... by acidified $\text{K}_2\text{Cr}_2\text{O}_7$*. This implies balancing the electrons transferred in the oxidation half-reaction against the reduction of the oxidizing agent, $\text{K}_2\text{Cr}_2\text{O}_7$.
The reduction half-reaction for dichromate ($\text{Cr}_2\text{O}_7^{2-}$) in acidic medium is: $\text{Cr}_2\text{O}_7^{2-} + 14\text{H}^+ + 6e^- \rightarrow 2\text{Cr}^{3+} + 7\text{H}_2\text{O}$ This reaction involves the gain of 6 electrons.
To balance the 6 electrons gained by dichromate, the oxidation of iodide must supply 6 electrons. The simple half-reaction $2\text{I}^- \rightarrow \text{I}_2 + 2e^-$ needs to be multiplied by 3 to provide 6 electrons: $3 \times (2\text{I}^- \rightarrow \text{I}_2 + 2e^-)$ $6\text{I}^- \rightarrow 3\text{I}_2 + 6e^-$ Therefore, the number of electrons involved in the oxidation of iodide in this context is X = 6.
We need to find the number of electrons (Y) involved when sulfide ion ($\text{S}^{2-}$) is oxidized to elemental sulfur (S) by acidified $\text{K}_2\text{Cr}_2\text{O}_7$.
The oxidation half-reaction is: $\text{S}^{2-} \rightarrow \text{S} + 2e^-$
Similar to the iodide case, we need to consider the electron transfer relative to the reduction of dichromate (which involves 6 electrons).
To balance the 6 electrons gained by dichromate, the oxidation of sulfide must supply 6 electrons. The half-reaction $\text{S}^{2-} \rightarrow \text{S} + 2e^-$ needs to be multiplied by 3 to provide 6 electrons: $3 \times (\text{S}^{2-} \rightarrow \text{S} + 2e^-)$ $3\text{S}^{2-} \rightarrow 3\text{S} + 6e^-$ Therefore, the number of electrons involved in the oxidation of sulfide in this context is Y = 6.
We found that X = 6 and Y = 6.
The total number of electrons is the sum: $ \text{X} + \text{Y} = 6 + 6 = 12 $
| Substance | $\Delta G_f^\circ / \text{kJ mol}^{-1}$ |
| $\text{A}_2$ | -100.00 |
| A | -50.832 |
Identify the correct statements :
A. Hydrated salts can be used as primary standard.
B. Primary standard should not undergo any reaction with air.
C. Reactions of primary standard with another substance should be instantaneous and stoichiometric.
D. Primary standard should not be soluble in water.
E. Primary standard should have low relative molar mass.
Choose the correct answer from the options given below :
| Substance | $\Delta G_f^\circ / \text{kJ mol}^{-1}$ |
| $\text{A}_2$ | -100.00 |
| A | -50.832 |
Identify the correct statements :
A. Hydrated salts can be used as primary standard.
B. Primary standard should not undergo any reaction with air.
C. Reactions of primary standard with another substance should be instantaneous and stoichiometric.
D. Primary standard should not be soluble in water.
E. Primary standard should have low relative molar mass.
Choose the correct answer from the options given below :