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Consider $\text{A} \xrightarrow{k_1} \text{B}$ and $\text{C} \xrightarrow{k_2} \text{D}$ are two reactions. If the rate constant ($k_1$) of the $\text{A} \longrightarrow \text{B}$ reaction can be expressed by the following equation $\log_{10} k = 14.34 - \frac{1.5 \times 10^4}{T/K}$ and activation energy of $\text{C} \longrightarrow \text{D}$ reaction ($\text{Ea}_2$) is $\frac{1}{5}$th of the $\text{A} \longrightarrow \text{B}$ reaction ($\text{Ea}_1$), then the value of ($\text{Ea}_2$) is _________ $\text{kJ mol}^{-1}$. (Nearest Integer)

Activation Energy Calculation

The problem requires calculating the activation energy ($\text{Ea}_2$) for the reaction $\text{C} \rightarrow \text{D}$, given the relationship between the rate constant ($k_1$) and temperature ($T$) for the reaction $\text{A} \rightarrow \text{B}$, and the ratio of their activation energies.

Deriving Ea1 from the Rate Constant Equation

The rate constant ($k_1$) for the reaction $\text{A} \rightarrow \text{B}$ is given by:

$ \log_{10} k_1 = 14.34 - \frac{1.5 \times 10^4}{T} $

The Arrhenius equation, expressed using base-10 logarithm, is:

$ \log_{10} k = \log_{10} A - \frac{E_a}{2.303RT} $

Comparing the given equation with the Arrhenius equation allows us to find the activation energy ($\text{Ea}_1$) for the first reaction. The term $\frac{1.5 \times 10^4}{T}$ corresponds to $\frac{E_{a1}}{2.303RT}$:

$ \frac{E_{a1}}{2.303RT} = \frac{1.5 \times 10^4}{T} $

This simplifies to:

$ \frac{E_{a1}}{2.303R} = 1.5 \times 10^4 $

Now, we solve for $\text{Ea}_1$ using the gas constant $R = 8.314 \text{ J mol}^{-1} \text{ K}^{-1}$:

$ E_{a1} = (1.5 \times 10^4) \times 2.303 \times R $

$ E_{a1} = (1.5 \times 10^4) \times 2.303 \times 8.314 \text{ J mol}^{-1} $

$ E_{a1} \approx 287191.82 \text{ J mol}^{-1} $

Convert $\text{Ea}_1$ to kilojoules per mole ($\text{kJ mol}^{-1}$):

$ E_{a1} \approx \frac{287191.82}{1000} \text{ kJ mol}^{-1} $

$ E_{a1} \approx 287.19 \text{ kJ mol}^{-1} $

Calculating Ea2

The problem states that $\text{Ea}_2 = \frac{1}{5} \text{Ea}_1$. We use the calculated value of $\text{Ea}_1$:

$ \text{Ea}_2 = \frac{1}{5} \times E_{a1} $

$ \text{Ea}_2 = \frac{1}{5} \times 287.19 \text{ kJ mol}^{-1} $

$ \text{Ea}_2 \approx 57.438 \text{ kJ mol}^{-1} $

Final Result

The question asks for the value of $\text{Ea}_2$ rounded to the nearest integer.

$ \text{Ea}_2 \approx 57 \text{ kJ mol}^{-1} $

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Similar Questions

  1. The cycloalkene (X) on bromination consumes one mole of bromine per mole of (X) and gives the product (Y) in which C:Br ratio is 3:1. The percentage of bromine in the product (Y) is _________%. (Nearest integer)
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  2. Dissociation of a gas $\text{A}_2$ takes place according to the following chemical reaction. At equilibrium, the total pressure is $1 \text{ bar}$ at $300\text{K}$.
    $\text{A}_2\text{(g)} \rightleftharpoons 2\text{A(g)}$
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    A-50.832

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  5. Consider the following electrochemical cell :
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Important Questions from Physical Chemistry

  1. The cycloalkene (X) on bromination consumes one mole of bromine per mole of (X) and gives the product (Y) in which C:Br ratio is 3:1. The percentage of bromine in the product (Y) is _________%. (Nearest integer)
    (Given : molar mass in $\text{g mol}^{-1} \text{ H} : 1, \text{ C} : 12, \text{ O} : 16, \text{ Br} : 80$)
  2. Dissociation of a gas $\text{A}_2$ takes place according to the following chemical reaction. At equilibrium, the total pressure is $1 \text{ bar}$ at $300\text{K}$.
    $\text{A}_2\text{(g)} \rightleftharpoons 2\text{A(g)}$
    The standard Gibbs energy of formation of the involved substances has been provided below:
    Substance$\Delta G_f^\circ / \text{kJ mol}^{-1}$
    $\text{A}_2$-100.00
    A-50.832

    The degree of dissociation of $\text{A}_2\text{(g)}$ is given by $(x \times 10^{-2})^{1/2}$ where $x =$ _________. (Nearest integer).
    $[\text{Given: } \text{R} = 8 \text{ J mol}^{-1}\text{ K}^{-1}, \log 2 = 0.3010, \log 3 = 0.48]$
    Assume degree of dissociation is not negligible.
  3. Which of the following mixture gives a buffer solution with pH = 9.25 ?
    Given : $\text{pK}_b (\text{NH}_4\text{OH}) = 4.75$
  4. Identify the correct statements :
    A. Hydrated salts can be used as primary standard.
    B. Primary standard should not undergo any reaction with air.
    C. Reactions of primary standard with another substance should be instantaneous and stoichiometric.
    D. Primary standard should not be soluble in water.
    E. Primary standard should have low relative molar mass.
    Choose the correct answer from the options given below :

  5. Consider the following electrochemical cell :
    $\text{Pt} \mid \text{O}_2\text{(g)}(1\text{bar}) \mid \text{HCl(aq)} \parallel \text{M}^{2+}\text{(aq, 1.0 M)} \mid \text{M(s)}$
    The pH above which, oxygen gas would start to evolve at anode is _________ (nearest integer).
    Given :
    $\begin{bmatrix} \text{E}^\circ_{\text{M}^{2+}/\text{M}} = 0.994 \text{ V} \\ \text{E}^\circ_{\text{O}_2/\text{H}_2\text{O}} = 1.23 \text{ V} \end{bmatrix} \text{standard reduction potential}$
    and $\frac{\text{RT}}{\text{F}} (2.303) = 0.059 \text{ V}$ at the given condition
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