The formation of a binary cation $(\text{EH}_x)^+$ and the reaction of $\text{EH}_3$ with Nessler's reagent ($\text{K}_2\text{HgI}_4$ in an alkaline medium) are crucial clues. The reaction with Nessler's reagent is characteristic of ammonia ($\text{NH}_3$), indicating that element E is likely Nitrogen (N), belonging to Group 15 of the p-block.
The question provides first ionization enthalpy ($\Delta H_{IE1}$) values for the first element of groups 13, 14, 15, and 16. Let's examine the typical $\Delta H_{IE1}$ values for these elements:
The given options are 1402, 801, 1312, and 1086 $\text{kJ mol}^{-1}$. These values correspond reasonably well to the first ionization enthalpies of N, B, O, and C, respectively.
While the Nessler's test strongly suggests E is Nitrogen (whose $\Delta H_{IE1}$ is 1402 $\text{kJ mol}^{-1}$, Option 1), the designated correct answer is 1312 $\text{kJ mol}^{-1}$ (Option 3). This value is very close to the $\Delta H_{IE1}$ of Oxygen (~1314 $\text{kJ mol}^{-1}$), the first element of Group 16.
Following the provided correct answer, we select 1312 $\text{kJ mol}^{-1}$ as the first ionization enthalpy for element E. This implies that, in the context of this question and its designated answer, element E corresponds to the value 1312 $\text{kJ mol}^{-1}$, which aligns with the element from Group 16.
Given below are two statements :
Statement I : $\text{C} < \text{O} < \text{N} < \text{F}$ is the correct order in terms of first ionization enthalpy values.
Statement II : $\text{S} > \text{Se} > \text{Te} > \text{Po} > \text{O}$ is the correct order in terms of the magnitude of electron gain enthalpy values.
In the light of the above statements, choose the correct answer from the options given below :
Given below are two statements :
Statement I : $\text{C} < \text{O} < \text{N} < \text{F}$ is the correct order in terms of first ionization enthalpy values.
Statement II : $\text{S} > \text{Se} > \text{Te} > \text{Po} > \text{O}$ is the correct order in terms of the magnitude of electron gain enthalpy values.
In the light of the above statements, choose the correct answer from the options given below :